To decide who pays for lunch, a passengeron a moving train tosses a coin straight upward with an initialspeed of 5.25 m>s and catches it again when it returns to its initial level. From the point of view of the passenger, then, the coin’sinitial velocity is 15.25 m>s 2yn . The train’s velocity relative to theground is 112.1 m>s2xn . (a) What is the minimum speed of the coinrelative to the ground during its flight? At what point in the coin’sflight does this minimum speed occur? Explain. (b) Find the initial speed and direction of the coin as seen by an observer on theground. (c) Use the expression for ymax derived in Example 4-14 tocalculate the maximum height of the coin, as seen by an observeron the ground. (d) What is the maximum height of the coin fromthe point of view of the passenger, who sees only one-dimensionalmotion?
To decide who pays for lunch, a passenger
on a moving train tosses a coin straight upward with an initial
speed of 5.25 m>s and catches it again when it returns to its initial level. From the point of view of the passenger, then, the coin’s
initial velocity is 15.25 m>s 2yn . The train’s velocity relative to the
ground is 112.1 m>s2xn . (a) What is the minimum speed of the coin
relative to the ground during its flight? At what point in the coin’s
flight does this minimum speed occur? Explain. (b) Find the initial speed and direction of the coin as seen by an observer on the
ground. (c) Use the expression for ymax derived in Example 4-14 to
calculate the maximum height of the coin, as seen by an observer
on the ground. (d) What is the maximum height of the coin from
the point of view of the passenger, who sees only one-dimensional
motion?
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