Three forces acting on an object are given by F, = (-1.9î + 5.80j) N, F, = (4.95î - 2.15j) N, and F, = (-44î) N. The object experiences an acceleration of magnitude 3.60 m/s. (a) What is the direction of the acceleration? • (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 14.0 s? m/s (d) What are the velocity components of the object after 14.0 s? (Let the velocity be denoted by v.) V = ( j) m/s

Three forces acting on an object are given by F, = (-1.9î + 5.80j) N, F, = (4.95î - 2.15j) N, and F, = (-44î) N. The object experiences an acceleration of magnitude 3.60 m/s. (a) What is the direction of the acceleration? • (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 14.0 s? m/s (d) What are the velocity components of the object after 14.0 s? (Let the velocity be denoted by v.) V = ( j) m/s

Name: Three forces acting on an object are given by F1 = (−1.9î + 5.80ĵ) N,
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: Three forces acting on an object are given by F1 = (−1.9î + 5.80ĵ) N, F2 = (4.95î − 2.15ĵ) N, and F3 = (−44î) N. The object experiences an acceleration of magnitude 3.60 m/s2. Three forces acting on an object are given by F, = (-1.9î + 5.80j) N, F, =

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 7P: A force F1 of magnitude 6.00 units acts on an object at the origin in a direction = 30.0 above the...

See similar textbooks

Related questions

Q: istance of 6 meters from rest, the force F is then removed. If F = 800 N, compute the velocity of…

A: let v be the velocity when force F is removed. Normal force on the block N=1500-Fsin30o…

Q: The resultant of three coplanar-concurrent forces is 200lb 90°. Determine the value and direction of…

Q: The following resultants are acquired after solving a 2-force system. Which among them has the…

A: Force is a vector quantity and their resultant is given by vector addition methods .

Q: As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air…

A: The forces on the ball along the vertical direction will be :The force exerted by the pitcher, F…

Q: A constant force P = 750 N acts on the body shown in figure during only the first 6m of its motion…

Q: An object of mass M hangs on a massless string of length 0.500 m attached to the ceiling. The object…

A: Figure shows the given question,

Q: According to legend, Galileo Galilei dropped two balls of different mass from the top of the leaning…

A: Gravity acceleration at Earth’s surface has been measured many times. In British Imperial Units,…

Q: A 1500N block is in contact with a level plane whose coefficient of kinetic friction is 0.10 If the…

A: Given: The weight of the block is 1500 N. The coefficient of kinetic friction is 0.1. The applied…

Q: Suppose a rocket is at an elevation of 100 km and has an initial velocity of 1.00 x 10^4 m/s…

A: Given:initial velocity u = 1*104 m/s initial height h = 100 km = 1*105 m

Q: In the example of a tennis ball being served, if the initial mass is 5kg and it accelerates from…

A: Given data: Mass (m) = 5 kg Initial velocity (V0) = 0 m/s Final velocity (Vf) = 45 m/s Distance…

Q: There are two forces on the 2.33 kg box in the overhead view of the figure but only one is shown.…

Q: After falling from rest from a height of 25 m, a 0.60-kg ball rebounds upward, reaching a height of…

Q: If, by some suitable mechanism, the falling body had been given an initial downward push instead of…

Q: In which case would it be easier to lift a cement truck: on Earth's surfade or on the Moon's…

Q: If a horizontal force is applied to an object, how can you tell if an object will start moving?

A: Static friction comes into act when a force is applied on the body and it tries to move the body.…

Q: A car of mass 1200 kg is accelerated from rest to a speed of 72 km/hr in 40 seconds. Calculate the…

A: Given data: Mass of car is, m=1200 kg. Initial speed of car is, u=0 m/s.…

Q: A 3.2 kg mass is initially at rest while upon a frictionless, horizontal surface. An applied force…

A: Given information: Here, m is the object’s mass, F is the force applied on the object, θ is the…

Q: A constant force is exerted on a cart that is initially at rest on a frictionless air track. The…

Q: An object of mass 0.53 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a…

A: Mass of object "m "= 0.53kg final velocity "v"= 13.4m/s time taken "t"= 2.9 ms = 2 .9×10^-³s…

Q: A block of ice with a mass of 2.50 kg is moving on a frictionless, horizontal surface. At t=0, the…

Q: As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air…

A: Given,

Q: Find the maximum value of the force F making angle 0 with the normal of the block of mass m such…

Q: A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/s comes to rest…

Q: When landing from a jump, Andy applied an average vertical force of -2500 N to the ground in order…

A: Given: Average vertical force, F=-2500 N Weight, W=-760 N Mass, m=77.5 kg Formula: Newton's Second…

Q: Professional Application - A car moving at 10 m/s crashes into a tree and stops in 0.26 s. Calculate…

A: Using kinematic equation, the expression for find acceleration is v=u+ata=v-ut Insert values in the…

Q: A block of mass m is initially at rest on a frictionless surface at the origin. At t═0 a decreasing…

A: Equation for v(t) vt=∫adt=∫Fmdt=Ftm+v0=Ftm+12 m/s

Q: Describe a situation in which the net external force on a system is not zero, yet its speed remains…

A: Consider a ball tied to a string which is undergoing circular motion at constant speed. The net…

Q: A cart that can move along a straight track has a mass of 3.00 kg and an initial velocity of 4.00…

A: In this question we are given that a cart that can move along a straight track has a mass of 3.00 kg…

Q: A stereo rests on a horizontal surface. The normal reaction of the surface on the stereo is 13N…

Q: As a protest against the umpire's calls, a baseball pitcher throws a ball straight up into the air…

A: According to the given condition, the initial speed (u) is zero and the final speed (v) is 22 m/s.…

Q: Istahp. A constant force F= 5.0 [N] is applied at a certain angle from the horizontal on a 0.50 [kg]…

Q: A dockworker applies a constant horizontal force of 80.ON to a block of ice on a smooth horizontal…

Q: bject of mass 0.69 kg is initially at rest. When a force acts on it for 2.9 ms it acquires a speed…

Q: A 2.9 kg mass is initially at rest while upon a horizontal surface. An applied force of 16 N is…

Q: A car moving at 30 m/s crashes into a tree and stops in 0.25 s. Calculate the force the seat belt…

A: Before finding the force we need to find the acceleration. Once we have acceleration, using the mass…

Q: After falling from rest from a height of 25 m, a 0.30-kg ball rebounds upward, reaching a height of…

A: Given information:The mass of the ball (m) = 0.3 kgHeight from which it falls (h1) = 25 mHeight to…

Q: A force acts on an object of mass 0.5 kg and accelerates it from rest to 0.2 m/s in 0.2 s. The…

Q: The position of a particle according to the appropriate coordinate set can be vectorially specified…

Q: t = 0 t 3.5 s vo = (2.5i + 3.5j) m/s i = (-2.51) m/s %3D The velocity of a 3.0-kg object is shown at…

A: t = 0 sec t1 = 3.5 secchange in time = 3.5 sec mass = 3 kg →vo = 2.5i^ + 3.5 j^→vf = -2.5 i^change…

Q: After falling from rest from a height of 31 m, a 0.40-kg ball rebounds upward, reaching a height of…

A: The velocity of ball when it touches the ground after falling from height 31 m is given as V² =…

Concept explainers

Newton's Second Law

Newton’s laws of motion describe the relationship between the motion of an object and forces acting on it. Newton’s law of motion has two types as follows:

Topic Video

Question

Three forces acting on an object are given by

F₁ = (−1.9î + 5.80ĵ) N,

F₂ = (4.95î − 2.15ĵ) N,

and

F₃ = (−44î) N.

The object experiences an acceleration of magnitude 3.60 m/s².

Three forces acting on an object are given by F, = (-1.9î + 5.80j) N, F, = (4.95î - 2.15j) N, and F, = (-441) N. The object experiences an acceleration of magnitude 3.60 m/s?.
(a) What is the direction of the acceleration?
° (counterclockwise from the +x-axis)
(b) What is the mass of the object?
|kg
(c) If the object is initially at rest, what is its speed after 14.0 s?
m/s
(d) What are the velocity components of the object after 14.0 s? (Let the velocity be denoted by v.)
m/s
=

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1 Given

Step 2

Step 3

Step 4

Step 5

Trending now

This is a popular solution!

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A force F1, of magnitude 6.00 units acts on an object at the origin in a direction = 30.0 above the positive x-axis (Fig. P3.8). A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2?. Figure P3.8
A 1.80x10^4 kg semi-trailer truck drives up a 200 m hill [θ = 30 degrees above horizontal], at a constant speed of 25.0 m/s. The force of friction is 6.00x10^2 N. Write an equation to isolate and solve for P.
Three forces acting on an object are given by F, = (-2.15î + 6.80j) N, F, = (4.80î – 2.5j) N, and F, = (-48.5î) N. The object experiences an acceleration of magnitude 3.90 m/s2. (a) What is the direction of the acceleration? ° (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 17.0 s? m/s (d) What are the velocity components of the object after 17.0 s? (Let the velocity be denoted by v.) v = ĵ) m/s
A variable force F(x)=Ax2-Bx acts on an object. The units of F(x) are N and the values of A and B are A=6.09 and B=3.18 when x is in meters. The units of A and B are?
Three forces acting on an object are given by F₁ = (-1.95î + 6.60ĵ) N, F₂ = (4.651 – 1.85ĵ) N, and F3 = (-43.51) N. The object experiences an acceleration of magnitude 3.65 m/s². (a) What is the direction of the acceleration? O (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 18.0 s? m/s (d) What are the velocity components of the object after 18.0 s? (Let the velocity be denoted by v.) î+ î) m/s
Three forces acting on an object are given by F, = (-1.75î + 5.50j) N, F, = (5.25î – 1.35j) N, and 3.60 m/s?. É, = (-41.5Î) N. The object experiences an acceleration of magnitude (a) What is the direction of the acceleration? ° (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 20.0 s? m/s (d) What are the velocity components of the object after 20.0 s? (Let the velocity be denoted by v.) m/s
A particle of mass 1.0 kg is subjected to a force Fiz = -3.0N and a second force of F2 = 14.0N.Calculate the magnitude of the acceleration, in m/s, of the particle. Use two significant digits please.
A net force of 3,000.0 N accelerates a car from rest to 37.4 km/h in 5.00 s. (a) What is the mass of the car? (b) What is the weight of the car? (а) т%3 x 10° kg sa (b) w = × 10ª N Next
An airliner of mass 1.70 * 105 kg lands at a speed of 75.0 m>s. As it travels along the runway, the combined effects of air resistance, friction from the tires, and reverse thrust from the engines produce a constant force of 2.90 * 105 N opposite to the airliner’s motion. What distance along the runway does the airliner travel before coming to a halt?
Three forces acting on an object are given by F₁ = (−2.2î + 6.85ĵ) N, F₂ = (4.75î – 1.25ĵ) N, and F3 = (-401) N. The object experiences an acceleration of magnitude 3.80 m/s². (a) What is the direction of the acceleration? 98.50 X Note that the direction of the acceleration is the same as the direction of the net force.° (counterclockwise from the +x-axis) (b) What is the mass of the object? 9.964 kg (c) If the object is initially at rest, what is its speed after 11.0 s? 41.8 m/s (d) What are the velocity components of the object after 11.0 s? (Let the velocity be denoted by v.) ✓ = -41.34 m/s +6.18
A particle of mass 1.2 kg is acted on by forces F, = 18î N, F, = -11î N, and F, = 9.0j N. What is its acceleration (in m/s?) in this case? (Express your answer in vector form.) m/s?
Three forces acting on an object are given by F1 = (−1.6î + 6.55ĵ) N, F2 = (4.75î − 1.2ĵ) N, and F3 = (−44.5î) N. The object experiences an acceleration of magnitude 3.90 m/s2. (a) What is the direction of the acceleration?_________° (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 11.0 s? m/s (d) What are the velocity components of the object after 11.0 s? (Let the velocity be denoted by v.) v = _______î +_____ ĵ m/s