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This reaction must have a ∆G<0 at SATP:
| Xe(g)+F2(g)→XeF2(g) | |
| 2Na(s)+Cl2(g)→2NaCl(s) | |
| 2NaF(s)+I2(s)→2NaI(s)+F2(g) | |
| MgSO4(s)→Mg(s)+S(s)+2O2(g) |
We have to consider entropy here.
We know,
G = H-TS
So a reaction proceed with generating high amount of entropy, then that generally give G<0 as follows:
G = H-TS
If S>> 0, then TS >>H
Step by step
Solved in 2 steps
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