This is the question I am stuck on - A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the first 10 people. Prompt the user for a name, and if the name is found in the list, display the corresponding phone number. If the name is not found in the list, prompt the user for a phone number, and add the new name and phone number to the list. Continue to prompt the user for names until the user enters quit. After the arrays are full (containing 30 names), do not allow the user to add new entries. Use the following names and phone numbers: Name Phone # Gina (847) 341-0912 Marcia (847) 341-2392 Rita (847) 354-0654 Jennifer (414) 234-0912 Fred (414) 435-6567 Neil (608) 123-0904 Judy (608) 435-0434 Arlene (608) 123-0312 LaWanda (920) 787-9813 Deepak (930) 412-0991 This is the code I have - import java.util.*; class PhoneNumbers { public static void main(String[] args) { // Write your code here int room,j=0; boolean present= false; String [] names ={"Gina", "Marcia", "Rita", "Jennifer", "Fred", "Neil", "Judy", "Arlene", "LaWanda", "Deepak"}; String [] number= {"(847) 341-0912","(847) 341-2392", "(847) 354-0654","(414) 234-0912", "(414) 435-6567", "(608) 123-0904", "(608) 435-0434", "(608) 123-0312", "(920) 787-9813", "(930) 412-0991" }; String nameEntered; Scanner input = new Scanner(System.in); //Continue until user enters quit while(true) { System.out.println("Please enter name: "); //enter name to be searched nameEntered = input.nextLine(); //if user enter quit if(nameEntered.equals("quit")) //Exit the program break; for(room = 0; room < names.length; room++) //search for the name { if(names[room].equals(nameEntered)) { present =true; //if found return true j=room; break; } } if(present==true) //check for true of false { System.out.println(names[j] + " corresponding number is " +number[j]); } //if name is not found enter new entries else { System.out.println("Name and phone number not found"); System.out.println("Enter new entries from user:"); //array for name and number to be entered by user String newname[]=new String[20]; String newnumber[]= new String[20]; for(int i=0;i

This is the question I am stuck on - A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the first 10 people. Prompt the user for a name, and if the name is found in the list, display the corresponding phone number. If the name is not found in the list, prompt the user for a phone number, and add the new name and phone number to the list. Continue to prompt the user for names until the user enters quit. After the arrays are full (containing 30 names), do not allow the user to add new entries. Use the following names and phone numbers: Name Phone # Gina (847) 341-0912 Marcia (847) 341-2392 Rita (847) 354-0654 Jennifer (414) 234-0912 Fred (414) 435-6567 Neil (608) 123-0904 Judy (608) 435-0434 Arlene (608) 123-0312 LaWanda (920) 787-9813 Deepak (930) 412-0991 This is the code I have - import java.util.*; class PhoneNumbers { public static void main(String[] args) { // Write your code here int room,j=0; boolean present= false; String [] names ={"Gina", "Marcia", "Rita", "Jennifer", "Fred", "Neil", "Judy", "Arlene", "LaWanda", "Deepak"}; String [] number= {"(847) 341-0912","(847) 341-2392", "(847) 354-0654","(414) 234-0912", "(414) 435-6567", "(608) 123-0904", "(608) 435-0434", "(608) 123-0312", "(920) 787-9813", "(930) 412-0991" }; String nameEntered; Scanner input = new Scanner(System.in); //Continue until user enters quit while(true) { System.out.println("Please enter name: "); //enter name to be searched nameEntered = input.nextLine(); //if user enter quit if(nameEntered.equals("quit")) //Exit the program break; for(room = 0; room < names.length; room++) //search for the name { if(names[room].equals(nameEntered)) { present =true; //if found return true j=room; break; } } if(present==true) //check for true of false { System.out.println(names[j] + " corresponding number is " +number[j]); } //if name is not found enter new entries else { System.out.println("Name and phone number not found"); System.out.println("Enter new entries from user:"); //array for name and number to be entered by user String newname[]=new String[20]; String newnumber[]= new String[20]; for(int i=0;i

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Chapter12: Exception Handling

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This is the question I am stuck on -

A personal phone directory contains room for first names and phone numbers for 30 people. Assign names and phone numbers for the first 10 people. Prompt the user for a name, and if the name is found in the list, display the corresponding phone number. If the name is not found in the list, prompt the user for a phone number, and add the new name and phone number to the list.

Continue to prompt the user for names until the user enters quit. After the arrays are full (containing 30 names), do not allow the user to add new entries.

Use the following names and phone numbers:

Name	Phone #
Gina	(847) 341-0912
Marcia	(847) 341-2392
Rita	(847) 354-0654
Jennifer	(414) 234-0912
Fred	(414) 435-6567
Neil	(608) 123-0904
Judy	(608) 435-0434
Arlene	(608) 123-0312
LaWanda	(920) 787-9813
Deepak	(930) 412-0991

This is the code I have -

import java.util.*;

class PhoneNumbers {

public static void main(String[] args) {

// Write your code here

int room,j=0;

boolean present= false;

String [] names ={"Gina", "Marcia", "Rita", "Jennifer", "Fred", "Neil", "Judy", "Arlene", "LaWanda", "Deepak"};

String [] number= {"(847) 341-0912","(847) 341-2392", "(847) 354-0654","(414) 234-0912", "(414) 435-6567", "(608) 123-0904", "(608) 435-0434", "(608) 123-0312", "(920) 787-9813", "(930) 412-0991" };

String nameEntered;

Scanner input = new Scanner(System.in);

//Continue until user enters quit

while(true)

{

System.out.println("Please enter name: ");

//enter name to be searched

nameEntered = input.nextLine();

//if user enter quit

if(nameEntered.equals("quit"))

//Exit the program

break;

for(room = 0; room < names.length; room++) //search for the name

{

if(names[room].equals(nameEntered))

{

present =true; //if found return true

j=room;

break;

}

if(present==true) //check for true of false

{

System.out.println(names[j] + " corresponding number is " +number[j]);

}

//if name is not found enter new entries

else

{

System.out.println("Name and phone number not found");

System.out.println("Enter new entries from user:");

//array for name and number to be entered by user

String newname[]=new String[20];

String newnumber[]= new String[20];

for(int i=0;i<newname.length;i++)

{

System.out.println();

System.out.println("Enter quit to stop adding names and numbers otherwise Enter the phone number:");

String temp=input.nextLine();

if(!temp.equals("quit"))

{

newnumber[i]=temp;

System.out.println("Enter name to the following phone number:");

newname[i]=input.nextLine();

}

else

{

System.out.println("The numbers are " +newnumber[i]); //print line for phone numbers

}

break;

}

I asked my teacher for help and he sent me this but it just confused me more -

When the user types in a name that is not in the phone book, the program should ask for the number and add it to the parallel arrays (space permitting). It looks like you have a second set of arrays where you add new numbers. The arrays should be declared size 30 and the first 10 positions filled. Something like this:

final int MAX_PHONEBOOK_SIZE = 30;

String[] myLittleBlackBookNames = new String[MAX_PHONEBOOK_SIZE];

String[] myLittleBlackBookNumbers = new String[MAX_PHONEBOOK_SIZE];

int nextPosition = 10;

boolean isFound = false;

myLittleBlackBookNames[0] = "Gina";

myLittleBlackBookNumbers[0] = "(847) 341-0912";

myLittleBlackBookNames[1] = "Marcia";

myLittleBlackBookNumbers[1] = "(847) 341-2392";

myLittleBlackBookNames[2] = "Rita";

myLittleBlackBookNumbers[2] = "(847) 354-0654";

myLittleBlackBookNames[3] = "Jennifer";

myLittleBlackBookNumbers[3] = "(847) 341-0912";

myLittleBlackBookNames[4] = "Fred";

myLittleBlackBookNumbers[4] = "(847) 341-0912";

myLittleBlackBookNames[5] = "Neil";

myLittleBlackBookNumbers[5] = "(608) 123-0904";

myLittleBlackBookNames[6] = "Judy";

myLittleBlackBookNumbers[6] = "(608) 435-0434";

myLittleBlackBookNames[7] = "Arlene";

myLittleBlackBookNumbers[7] = "(608) 123-0312";

myLittleBlackBookNames[8] = "LaWanda";

myLittleBlackBookNumbers[8] = "(920) 787-9813";

myLittleBlackBookNames[9] = "Deepak";

myLittleBlackBookNumbers[9] = "(930) 412-0991";

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