i need the answer quickly This code segment read theelements for the array M(10) usinginput box, then calculate the product(the result of multiplying) ofelements greater than the number 5.Then print the final result of themultiplication.1-..For I 1 To 10M(I) = InputBox("M")2-..3-............4-.5-..6-..........1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(1) 4-Next 5- End If 6-Print P1-P = 0 2-1f M(I) > 5 Then 3-P = P * M(I) 4-EndIf 5-Next 6-Print P1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-EndIf 5-Next 6-Print P1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-EndIf 5-Print P 6-Next1-P = 1 2-lf M(I) <=5 Then 3-P = P * M(I) 4-EndIf 5-Next 6-Print P

The correct answer is given below with a proper explaantion

This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. 1-............ For I 1 To 10 M(I) = InputBox("M") 2-... 3-.. 5-... 6-.. 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(1) 4- Next 5- End If 6-Print P 1-P = 0 2-1f M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Print P 6-Next 1-P = 1 2-lf M(I) <=5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P O O

This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. 1-............ For I 1 To 10 M(I) = InputBox("M") 2-... 3-.. 5-... 6-.. 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(1) 4- Next 5- End If 6-Print P 1-P = 0 2-1f M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Print P 6-Next 1-P = 1 2-lf M(I) <=5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P O O

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter7: Arrays

Section7.3: Declaring And Processing Two-dimensional Arrays

Problem 7E: (Electrical eng.) a. An engineer has constructed a two-dimensional array of real numbers with three...

See similar textbooks

Similar questions

This code segment generate an array 5-by-5 showing that each element in the upper triangle is equal to 0, each element in the diagonal is equal to 1, and each element in the lower triangle is equal to 5. For I 1 To 5 For j = 1 To 5 1-....... 2-.. 3-.. 4-.. 5-. 6-.... End If Next j Next I O 1-If I j 6-A(I, j) = 1 1-If I j Then 2-A(1, j) = 0 3-Else if I
This code generate a 5-by-5 Array to display an array numbers showing that * each element in the main diagonal is equal to O For I = 1 To 5 For j = 1 To 5 1-..... 2-..... 3-.... 4-.... End If Next j Next I 1-lf I = j Then 2-A(I, j) = 0 3-Else 4-A(I, j) = InputBox(1) 1-If I j Then 2-A(I, j) = 0 3-Else 4-A(I1, j) = InputBox(1) %3D 1-lf A(I.j) = j Then 2-1, j = 0 3-Else 4-A(I, j) = InputBox(1) %3D
This code calculate the SUM of elements in each column of array T(5,3) and stored in array K(3). For I = 1 To 5 For J = 1 To 3 T(I, J) = InputBox("T") Next J, I 1-............ 2-... 3-..... Sum Sum + T(I, J) - 4-.. 5-....... Next J 1-For I = 1 To 3 2-Sum = 0 3-For J= 1 To 54- Next I 5-K(J) = Sum 1-For J = 1 To 3 2-Sum = 0 3-For I = 1 To 54- Next I 5-K(J) = Sum 1-For J = 1 To 5 2-Sum = 0 3-For I = 1 To 3 4- Next I 5-K(J) = Sum 1-For J = 1 To 3 2-Sum = 0 3-For 1 = 1 To 54- Next I 5-K(1) = Sum 1-Sum 02-For J = 1 To 3 3-For I = 1 To 54- K(J) = Sum 5-Next I
This code calculate the SUM of elements in each column of array T(5,3) and stored in array K(3). For I = 1 To 5 For J=1 To 3 T(I, J) = InputBox("T") Next J, I 1-.......... 2-.... 3-..... Sum Sum + T(I, J) = 4-.......... 5-.. Next J 1-Sum = 0 2-For J = 1 To 3 3-For I = 1 To 5 4-K(J) = Sum 5-Next I 1-For J = 1 -Sum = 0 3-For I = 1 To 5 4-Next I 5-K(1) = Sum 1-For I 1 To 3 2-Sum = 0 3-For J= 1 To 54- Next I 5-K(J) = Sum 1-For J = 1 To 5 2-Sum = 0 3-For I = 1 To 3 4-Next I 5-K(J) = Sum 1-For J = 1 To 3 2-Sum = 0 3-For I = 1 To 5 4-Next I 5-K(J) = Sum
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5 in array M(10). Then * .print the final result of the product 1-. . For I = 1 To 10 M(I) = InputBox("M") 2-.... 3-... 4..... 5-.... 6-.......
! This code create the one dimension array (B) contains the positive value of two dimension array A(4,3). 1-....... 2-.... 3-.... 4-.. 5-... 6-... End If Next 1-K-0 2-For I = 1 To 4 3-For J=1 To O 34-lf A(1,J) mod 2 = 0 Then 5-k = k + 1 6-B(K) = A(I,J) 1-K-0 2-For I = 1 To 4 3-For J=1 To O3 4-lf A(1,J) > 0 Then 5-k = k + 1 6- B(K) = A(I,J) 1-K-0 2-For I = 1 To 3 3-For J=1 To O 44-lf A(1,J) > 0 Then 5-k = k + 1 6- B(K) = A(I,J) 1-K-0 2-For I = 1 To 4 3-For J=1 To 3 4-lf A(1,J): > 0 Then 5-k = k + 1 6- A(I,J) =B(K) 1-K-1 2-For I = 1 To 4 3-For J=1 To
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. 1-.. For I 1 To 10 M(I) = InputBox("M") 2-.......... 3-..... 4-........ 5-......... 6-.......
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5 in array M(10) then print the final result of the multiplication. 1-............ For I = 1 To 10 M(I) = InputBox("M") 2-...... 3-.. 4-..... 5-.... 6-.......... 1-P = 1 2-lf M(I) 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P 1-P = 0 2-lf M(1) > 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P 1-P = 12-lf M(I) > 5 Then 3-P = P * M(I) 4- Next 5- End If 6-Pr
This code create the one dimension array (B) contains the positive value of two dimension array A(4,3). 1-..... 2-... 3-...... 4-.. 5-.... 6-.. End If Next O O O O 1-K-0 2-For I = 1 To 4 3-For J=1 To 3 4-lf A(I,J) > 0 Then 5-k = k + 1 6- A(I,J) =B(k) 1-K-0 2-For I = 1 To 3 3-For J=1 To 4 4-lf A(I,J) > 0 Then 5-k = k + 1 6-B(k) = A(I,J) 1-K-0 2-For I = 1 To 4 3-For J=1 To 3 4-lf A(I,J) mod 2 = 0 Then 5-k = k + 1 6-B(k) = A(I,J) 1-K-0 2-For I = 1 To 4 3-For J=1 To 3 4-lf A(I,J) > 0 Then 5-k = k + 1 6-B(k) = A(I,J) 1-K-1 2-For I = 1 To 4 3-For J=1 To 3 4-lf A(I,J) < 0 Then 5-k = k + 1 6-B(k) = A(I,J)
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. 1-............ For I 1 To 10 M(I) = InputBox("M") 2-.. 3-.. 4-.. 5-... 6-... 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Print P 6-Next 1-P = 1 2-lf M(I) 5 Then 3-P = P * M(I) 4-Next 5- End If 6-Print P 1-P = 0 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4-End If 5-Next 6-Frint P O O O O
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. For I 1 To 10 = M(I) = InputBox("M") 2-............ 3-.... 4-. 5-... 6-.... 1-P = 1 2-If M(I) > 5 Then 3-P = P * M(I) 4- End If 5-Print P 6-Next 1-P = 0 2-If M(I) > 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P 1-P = 1 2-lf M(I) 5 Then 3-P = P * M(I) 4- Next 5- End If 6-Print P 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P
This code segment read the elements for the array M(10) using input box, then calculate the product (the result of multiplying) of elements greater than the number 5. Then print the final result of the multiplication. 1-. For I=1 To 10 M(I) InputBox("M") 2-.......... 3-. 4-. 5-........... 6-.......... 1-P = 1 2-lf M(I) > 5 Then 3-P = P * M(I) 4- End If 5-Print P 6-Next 1-P = 0 2-1f M(1) > 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P 1-P = 1 2-lf M(I) 5 Then 3-P = P * M(I) 4- End If 5-Next 6-Print P visual Basic