This buggy code wants to create an integer array of size 10, whose values are the integers from 1 to 10. Fix it! Answer: (penalty regime: 10, 20, ... %) Reset answer 1 int a[10]; 2 int i; 3 4- for (i=1; i<-10; i++) { - a[i] = i; }
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![This buggy code wants to create an integer array of size 10, whose values are the integers from 1 to 10. Fix it!
Answer: (penalty regime: 10, 20, ... %)
Reset answer
1234569
4▾
int a[10];
int i;
for (i=1; i<=10; i++) {
a[i] = i;
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F45cf69fb-b0ff-4b62-bc2e-e4054fc1f593%2F3b4fba7b-6f93-44bd-b5be-aa75f128f9c3%2F0dqb30j_processed.png&w=3840&q=75)
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- Instrument shellsort to print the number of compares divided by the array sizefor each increment. Write a test client that tests the hypothesis that this number is asmall constant, by sorting arrays of random Double values, using array sizes that areincreasing powers of 10, starting at 100Please code in python.Given an array of integers a of even length, your task is to split it into two arrays of equal length such that all the numbers are unique in each of them. There may be more than one possible answer, in which case you may return any of them. If there are no possible answers, return an empty array. Hint: Count the number of occurrences of each integer in a. If there are integers occurring more than twice, then there is no solution. Next, put the integers occurring twice into both answer arrays. Finally, put all other numbers in the answer arrays, following the condition that they should have equal sizes. Example • For a = [2, 1, 2, 3, 3, 4], the output can be solution(a) = [[2, 1, 3], [2, 3, 4]]. Answers like [[1, 2, 3], [2, 3, 4]] or [[4, 2, 3], [3, 2, 1]] would also be considered correct. • For a = [1, 2, 2, 1], the output can be solution(a) = [[1, 2], [2, 1]]. Again, there are other possible answers. • For a = [2, 2, 3, 3, 2, 2], the output should be solution(a)…Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example:(in java) Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {
- Suppose that you are playing a card game whose goal is to collect exactly k cards with a total value of t. Write a solution that can determine if it is possible for a given collection of cards whose values are given in the array values. For example, if the array contained the values <10,5,7,2>, k = 3, and t = 12, you would return false because no three values add to 12. However, if t = 14, you would return true, since 5 + 7 + 2 = 14. So I considered this to be a form of groupSum recursion, so I try to implement it in recursion form. However, since the passing parameters are not the incrementing level index but 'k' that is the limit number of the numbers we can choose from the array, I cannot use passing index through recursion to search from the start of the array toward the end of the values.length(the length of the array). would there be any method I can use to increment and search along the array using k, the number of numbers we can add into the total(t) instead of the…Write method findZero, as started below. findZero should return the index of the first element of array A that contains the value zero, starting from position 0 up through position pos. If no element of A from position 0 to position pos contains the value zero, then findZero should return –1. For example: Array (A) Position (pos) Value returned by findZero(A, pos) 1 0 2 5 6 0 -1 1 0 2 5 6 1 1 1 0 2 5 6 2 1 1 0 2 0 6 2 1 1 0 2 0 6 4 1 1 2 3 4 5 4 -1 Complete method findZero below. Assume that it is called only with values that satisfy its assumptions as stated below. // Description: Returns smallest index k // such that (0 <= k <= pos) and (A[k] == 0) // Assumptions: 0 <= pos < A.length public int findZero(int[] A, int pos) {If x is an array of interger, then the value of &x[i] is same as A. &x[i-1] + sizeof (int) B. x + sizeof (int) * i C. x+i D. none of these
- How do I remove duplicate elements in an char array? This is my code, but it doesn't work: const int TEST1_NRULES = 4; char test1win[4][MAX_WORD_LENGTH+1] = { "stop", "no", "no", "no" }; char test1wout[4][MAX_WORD_LENGTH+1] = { "family", "ik", "bob", "bro" }; for (int i = 0; i < TEST1_NRULES; ++i) { for (int p = i + 1; p < TEST1_NRULES; ++p) { if (strcmp(test1win[i], test1win[p]) == 0) for (int k = i; k < TEST1_NRULES; ++k) { for (int j = 0; j < MAX_WORD_LENGTH; ++j) { test1win[k][j] = test1win[k + 1][j]; } } } }The rotateLeft method takes an array of integers, and an integer number of places, and returns a new copy of the array that contains a "rotated" version of the input array. Rotation means that elements have been shifted leftwards by that number of places, moving elements off one end of the array and onto the other end. For example, [11, 12, 13, 14, 15] rotated left by 2 places results in [13, 14, 15, 11, 12].in java Create two arrays with same length n: - Array A with integer numbers that user will insert- Array B with random numbers from 0 to 100.- Find sum of both arrays,- Find maximum values of both array and compare them: .if maximum of 1 st is lower then maximum of 2nd array: print sums of both arrays.if maximum of 1st is greater then maximum of 2nd array print 2nd array (use println)otherwise print first array in reverse.
- public static void reverseAscendingSubarrays(int[] items) Rearrange the elements of the given array of integers in place (that is, do not create and return a new array) so that the elements of every maximal strictly ascending subarray are reversed. For example, given the array {5, 7, 10, 4, 2, 7, 8, 1, 3}, after executing this method, the elements of the array would be {10, 7, 5, 4, 8, 7, 2, 3, 1}. Given another argument array {5, 4, 3, 2, 1}, the contents of that array would stay as {5, 4, 3, 2, 1} seeing that its each element is a maximal ascending subarray of length one. public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire…In Javascript, write code that prints the FIRST NAMES ONLY of people who have BOTH above average English grades AND below average age. Special conditions: Cannot use any array type built-in functions except filter(), map(), and reduce().Write a method SortTheEvens(), that first shifts all the even numbers of an input array to the left side in that array and then sorts all even numbers in that array.Note: You are not allowed to use direct indexing and can only use ptr++ and ptr-- operators. i.e. *(ptr + i) and ptr[i] are not allowed.Do using c++ programming language.