5.STOICHIOMETRY OF CELL GROWTH. Candida utilis is a yeast that is approved for use as a food additive, andis used in industrial production of carotenoids and other biochemicals. A batch cell culture of Candida utilisgrowing on glucose (C6H12O6) and ammonia (NH3) is used to grow additional cells under aerobic conditions.Given feeds of 550 g glucose, 230 g ammonia and 280 g oxygen (O₂) (assume O₂ is bubbled through so that all280 g are easily accessible to the cells}:A. Which nutrient is the limiting nutrient?B. What mass of new cells (dry basis) will be produced when the limiting nutrient is fully consumed?(Assume that the cells stay in exponential growth phase until all of this nutrient is consumed.)C. Write the balanced stoichiometric equation for cell growth.D. What is the respiratory quotient (RQ) for this cell growth?Notes: There are two values for cell formula for Candida Utilis growing on glucose. Use the first entry with a specificgrowth rate of 0.08 h¹. Yields based on glucose and O₂ are in Table 6.1. The cell yield per gram of ammonia consumed (ifit is the limiting reactant), YX/NH3 = 1.44 g/g.

INTRODUCTION In order for cells to grow, they require certain nutrients such as glucose, ammonia,…

Answered: There are two values for cell formula…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

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Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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A marine microorganism contains an enzyme that hydrolyzes glucose-6-sulfate. The activity test is based on the measurement of the rate of glucose formation. The enzyme in a cell-free extract has a KM of 6.7 x 10-9 M and a Vmax of 300 nM min-1 . Galactose-6-sulfate is a competitive inhibitor of the enzyme. To a concentration of glucose-6-sulfate 2 x 10-5 M and galactose-6-sulfate 10-5 M, the speed initial is 1.5 nM min-1 . Calculate the Ki for galactose-6-sulfate.
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During cheese production, LAB convert lactose to lactate and casein (milk protein) to amino acids. Lactate and amino acids then become the substrates for further microbial growth, which results in aroma production and deacidification of the cheese. The yeast Yarrowia lipolytica grows on the surface of many cheeses; it is capable of both lactate and amino acid catabolism. When grown on a lactate plus amino acid medium, Y. lipolytica preferentially consumes amino acids. Amino acid degradation results in the release of ammonia, which increases the pH. Draw a flow chart that shows the LAB fermentation of milk, followed by the growth of Y. lipolytica. Indicate which substrates are consumed first and what happens to the pH. Based on this simplified scenario, why do you think most cheeses involve the activity of more than one yeast species?
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Enzyme hydrolysis of glucose-6-sulfate occurs in a marine microorganism. The activity test is based on the rate at which glucose is metabolized. Its KM is 6.7 x 10-9 M and its Vmax is 300 nM min-1 in cell-free extract. Galactose-6-sulfate competes with the enzyme to inhibit it. When glucose-6-sulfate and galactose-6-sulfate are present at 2 x 10-5 M, the starting speed is 1.5 nM min-1. Take a look at the Ki for galactose-6-sulfate and figure out what it is.
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There are two values for cell formula for Candida Utilis growing on glucose. Use the first entry with a specific rate of 0.08 h¹. Yields based on glucose and O₂ are in Table 6.1. The cell yield per gram of ammonia consumed (if limiting reactant), YX/NH3 = 1.44 g/g.