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Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then. f'(x) = B'(x)T'(x) – T'(x)B′(x) - [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = f'(x) = B(x)T'(x)+T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) [B(x)]2 B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]2

Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then. f'(x) = B'(x)T'(x) – T'(x)B′(x) - [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = f'(x) = B(x)T'(x)+T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) [B(x)]2 B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]2

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.3: Algebraic Expressions
Problem 20E
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Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then B'(x)T'(x) T'(x)B'(x) - f'(x) = [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = B(x)T'(x) + T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) f'(x) = = [B(x)]² B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]²
Transcribed Image Text:Theorem: Quotient Rule If f(x) = T(x) B(x) is the quotient of differentiable functions, then B'(x)T'(x) T'(x)B'(x) - f'(x) = [B'(x)]2 T'(x) f'(x) = B'(x) f'(x) = B(x)T'(x) + T(x)B′(x) [B(x)]2 - B(x)T'(x) T(x)B'(x) f'(x) = = [B(x)]² B(x)T'(x) – T(x)B′(x) - f'(x) = [B'(x)]² B'(x)T(x) T'(x)B(x) f'(x) = [B(x)]²
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