The "White Eyes" gene in fruit flies is a "sex-linked" trait. What data demonstrated this? The white eye phenotype showed up in 25% of the F2 generation, but only on males All Females have white eyes in fruitflies The white eye phenotype showed up in 25% of the F2 generation, but only on females The white eye phenotype showed up on all of the males in the F2 generation
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The "White Eyes" gene in fruit flies is a "sex-linked" trait. What data demonstrated this?
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The white eye |
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All Females have white eyes in fruitflies |
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The white eye phenotype showed up in 25% of the F2 generation, but only on females |
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The white eye phenotype showed up on all of the males in the F2 generation |
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- About 40% of Solomon Islanders carry a gene for blond hair, and yet only 5%–10% of these people actually have blond hair. Why is the number of people with blond hair only 5%–10% when so many people carry genes for blond hair? The duck-billed platypus has a unique mechanism of sex determination: females have five pairs of X chromosomes (X1X1X2X2X3X3X4X4X5X5) and males have five pairs of X and Y chromosomes (X1Y1X2Y2X3Y3X4Y4X5Y5). Do you think each of the X and Y chromosome pairs in males assort independently of other X and Y pairs during meiosis? Why or why not? How is the inheritance of X-linked traits different from the inheritance of autosomal traits? How is the inheritance of X-linked and autosomal traits similar? List as many differences and similarities as you can.When the F1 bees were backcrossed to the inbred resistant line produced 4 types of offspring in equal numbers: ¼ if the back-cross offspring showed the complete hygienic behavior pattern ¼ of the back-cross offspring showed none of the elements of hygienic behavior ¼ of the back-cross offspring would uncap the cells of the diseased larvae but these workers would not remove the diseased larvae ¼ of the back-cross offspring would remove the diseased larvae (once the experimenter had uncapped the cells of the diseased larvae) Is it possible that two gene loci are involved in the resistant behavior? Justify your answer.The genes for sepia eye color, short bristles, and dark body coloration are on the same chromosome of Drosophila melanogaster. Each gene has two alleles: wild type, which is dominant, or mutant, which is recessive. se+ is dominant and causes red eyes; se is recessive and causes sepia eyes sb+ is dominant and causes long bristles; sb is recessive and causes short bristles b+ is dominant and causes gray body coloration; b is recessive and causes dark body coloration The sepia gene and short bristle gene are separated by 33 map units; the short bristle gene and the dark body gene are separated by 12 map units. The sepia gene and dark body gene are separated by 45 map units. If you crossed a fly, which was homozygous for the wild type allele of each gene (and had the phenotypes red eyes, long bristles, and gray body) with a homozygous recessive fly for each gene (and had the phenotypes sepia eyes, short bristles, and dark body coloration), the F₁ generation would entirely consist of flies…
- NLFN3, a gene in the X chromosome has been linked to Autism spectrum disorder ASD. Research has shown that the mutation R451C (represented by the allele X+) is recessive and causes ASD. Ear lobes in humans are coded by a single gene which displays simple dominance. E results in free earlobes, and e corresponds to attached earlobes. What is the probability of having a female offspring with ASD symptoms and attached earlobes from X+Y Ee and X+X ee parents? 25% O 100% 0% O 75% O 12.5% O 50%What specific observations (evidence) support the conclusions about sex determination in Drosophila and humans? Sort each observation to the appropriate bin. If an observation applies to both Drosophila and humans, sort it to the "Both" bin. If an observation does not apply to either Drosophila or humans, sort it to the "Neither" bin. Reset Help Three sets of autosomes per X chromosome are required for male fertility. Sex chromosomes are heteromorphic. Maleness is determined by lack of X chromosomes. Triploid individuals (3n) could be phenotypically normal females. XO individuals are male. More than one Y chromosome is needed for maleness. Diploid XXY individuals are abnormal males. Drosophila only Humans only Both Neither Submit Request AnswerWhen the F1 bees were backcrossed to the inbred resistant line produced 4 types of offspring in equal numbers: ¼ if the back-cross offspring showed the complete hygienic behavior pattern¼ of the back-cross offspring showed none of the elements of hygienic behavior¼ of the back-cross offspring would uncap the cells of the diseased larvae but these workers would not remove the diseased larvae¼ of the back-cross offspring would remove the diseased larvae (once the experimenter had uncapped the cells of the diseased larvae) 1. Is it possible that two gene loci are involved in the resistant behavior? Show work.
- Fruit flies (Drosophila) were mated. Cross #1 - 2 male red eyes (se+), wild wings(ap+) X 4 female red eyes (se+), wild wings(ap+) Cross #2 - 2 male sepia eyes(se-), apterous wings (ap-) X 4 female red eyes(se+), wild wings (ap+) Cross #3 - 2 male red eyes (se+), wild wings(ap+) X 4 female sepia eyes(se-), apterous wings(ap-) Cross #4 - 2 male sepia eyes(se-), apterous wings (ap-) X 4 female sepia eyes(se-), apterous wings(ap-) Write out a dihybrid cross and branch diagram for the F2 generation.You set up a cross between a male fruit fly with lobe eyes and a true breeding female fruit fly with reduced bristles and disrupted wings. In the F1 offspring you see the all the flies have WT bristles and WT wings. However, half the flies have WT eyes and half the flies have lobe eyes. You take 20 of the F1 female flies with lobe eyes and mate them to 20 true breeding male flies with reduced bristles and disrupted wings and observe the following offspring: 169 lobe eyes and reduced bristles 137 lobe eyes and disrupted wings 637 reduced bristles and disrupted wings 158 reduced bristles 36 wildtype 174 disrupted wings 657 lobe eyes 32 lobe eyes reduced bristles and disrupted wings Fruit flies are unusual in that the male fruit flies do not undergo crossovers during meiosis. If you had taken 20 of the F1 Males with lobe eyes and crossed them to 20 females that were true breeding for reduced bristles and disrupted wings what phenotypes and in what proportions would you expect in the…Please explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…
- In Drosophila the following genes are on the second chromosome Flight gene The dominant allele F can fly, the recessive allele f can not fly Eye color gene The Dominant allele R has red eyes, the recessive allele r has brown eyes You take flies which are FR/FR and cross them to flies which are fr/fr You then take the offspring from that and cross them with flies which are fr/fr You get the following numbers of offspring Can fly and have red eyes 50 Can not fly and have brown eyes 45 Can fly and have brown eyes 5 Can not fly and have red eyes? 7 (A) Which of the above offspring are recombinant? (B) What is the map distance between the genes?Bicoid is a maternal-effect gene in the fruit fly Drosophila that controls anterior/posterior axis formation. Recessive mutations in bicoid can result in fly larvae that have no head, and thus are embryonic lethal. bcd+ is the wild type bicoid allele bcd is the recessive mutant bicoid allele A cross between two heterozygous parents (bcd+/bcd) results in all wild-type F1 offspring. 1. What are the possible genotypes and ratios of each genotype in the F1 offspring of this cross? 1. How can you explain the fact that all the F1 offspring are phenotypically wild-type, using what you know about maternal-effect genes?You want to predict the possibility of two parent monsters having offspring with purple eyes and spiky fur. If a monster homozygous for purple eyed spiky fur mates with a heterozygous monster with green eyes and feathery fur, what are their genotypes? (Same as before, green and feathery are dominant) ggFf x GgFf 88FF x GgFf O GGFF x GGFF ggff x GgFf
