The trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a through e. The arrow has initial speed Vo and is launched at angle O to the horizontal. The vertical dashed lines represent equal time interval, At. (Note: g = 9.81 m/s²) m/s2) a Vo x(m). At point c the horizontal velocity is: Vo cos (0) Vo cos (0) + ½ g (2At)2 Vo sin (0) + ½ g (2At)2 Vo sin (0) – ½ g (2At)² (u)A

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter4: Motion In Two And Three Dimensions
Section: Chapter Questions
Problem 41P: At a particular instant, a hot air balloon is 100 m in the air and descending at a constant speed of...
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The trajectory of an arrow traveling in Earth's gravity without air resistance is shown
below at points a through e. The arrow has initial speed Vo and is launched at angle
O to the horizontal. The vertical dashed lines represent equal time interval, At.
(Note: g = 9.81 m/s2)
d
e
Vo.
х(m).
At point e the horizontal velocity is:
Vo cos (0)
Vo cos (0) + ½ g (2At)2
Vo sin (0) + ½ g (2At)2
Vo sin (0) – ½ g (2At)²
(u)A
Transcribed Image Text:The trajectory of an arrow traveling in Earth's gravity without air resistance is shown below at points a through e. The arrow has initial speed Vo and is launched at angle O to the horizontal. The vertical dashed lines represent equal time interval, At. (Note: g = 9.81 m/s2) d e Vo. х(m). At point e the horizontal velocity is: Vo cos (0) Vo cos (0) + ½ g (2At)2 Vo sin (0) + ½ g (2At)2 Vo sin (0) – ½ g (2At)² (u)A
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