The term 'duplex' refers to the ability of the data receiving stations to echo back a confirming message to the sender. In full duplex data transmission, both the sender and the receiver A) can send or receive data one at a time B) can receive and send data simultaneously C) can do one way data transmission only D) cannot talk at once
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- The Modem is the most well-known kind of Data Communication Equipment. It modulates an analog carrier signal in order to encode digital information, and it also demodulates such a carrier signal in order to decode the information that has been sent. To do this, a signal must be created that can be readily transferred and decoded in order to replicate the original digital data. Provide a brief explanation of how the modem accomplishes these objectives.What causes asynchronous transmission to have a non-constant duration between bytes?In GSM, there are 8 separate time slots that makeup what is known as a "TDMA frame". Each GSM time slot lasts for 577 ps (microseconds) and contains more than simply a sample of each individual signal. i. How long does the TDMA frame last, express your answer in his and ms? Each time slot comprises a total of 148 bits. Of these 148 bits, only 114 represent voice or other data. The rest are used for a variety of control purposes. How many bits of data are in one TDMA frame? How many bits for control purposes are in one TDMA frame? What is the total number of bits, including data and control, in a TDMA frame?
- The most familiar type of Data Communication Equipment is the Modem.it modulates an analog carrier signal to encode digital information and also demodulates such a carrier signal to decode the transmitted information. The goal is to produce a signal that can be transmitted easily and decoded to reproduce the original digital data. Briefly describe how these goals are achieved by the modem.Suppose that a binary message – either 0 or 1 – must be transmitted by wire from location Ato location B. However, the data sent over the wire are subject to a channel noise disturbance,so to reduce the possibility of error, the value 2 is sent over the wire when the message is1, and the value −2 is sent when the message is 0. If X, X = {−2,2}, is the value sent atlocation A, the value received at location B, denoted as R, is given byR = X + N ,where N is the channel noise disturbance, which is independent of X. When the message isreceived at location B, the receiver decodes it according to the following rule:if R ≥.5, then conclude that message 1 was sentif R < .5, then conclude that message 0 was sentAssuming that the channel noise, N, is a unit normal random variable and that the message0 or 1 is sent with equal probability, what is the probability that we conclude that the wrongmessage was sent? This is the probability of error for this communication channelBoth an isochronous connection and a synchronous connection may be understood better by examining the similarities and differences between the two kinds of connections.
- Your challenge is to use MATLAB to plot a received signal at a base station in a multipath channel when the transmitter sends a sinusoidal carrier signal. A transmitter sends a sinusoidal signal of frequency 1.5 MHz to the base station. There is a line-of-sight (LoS) path to the base station receiver, with delay 1 usec. The signal on this path is attenuated in amplitude by a factor 0.9 (the LoS amplitude gain). There are also three single bounce paths, one of delay 2 usec, with an amplitude gain of 0.5, one of delay 7 usec, with an amplitude gain of 0.4, and a third of delay 10 usec, with amplitude gain of 0.2. These parameters are fixed and do not change during the transmission. The project is to write MATLAB code to obtain the signal received at the receiver. Plot the signal over a time interval of 20 usec, including axes, and provide units for the time axis. Then answer the following questions: a) How is the output signal frequency related to the input signal frequency? b) Does the…Senders A and Senders B want to send data A d = 101 and B d = 100 respectively usingCDMA technology.The key sequences are A k = 010100100010110011 and B k = 000110101000010111.Using timing diagram perform coding and restructuring of signals.For the following stream of digital signal which is being transmitted by bit rate 5 Kbps: 101100000000110 a) Draw the waveform for all line codes you studied. b) Determine if the line code is self synchronized or not. c) Determine if the code can be used with ac coupling or not d) Determine the Bandwidth of the line code e) Which code is used in magnetic recording f) Which code is used in LAN
- What causes the difference in the amount of time that passes between each byte during asynchronous transmission?The reason for the varying duration between bytes in asynchronous transmission.Transmission delay is: The time taken from the circuit in the receiver side to demodulate the signal (caused by logical circuits). None is true. The time taken from the circuit in the host side to transmit the signal (caused by logical circuits). The time taken from the circuit in the host side to receive the signal (caused by logical circuits). The time taken from the circuit in the host side to modulate the signal (caused by logical circuits).