The state of stresses in the x and y directions at a point in a given material is shown in the figure below. If the value of the shear stress in the x-y axes T, is 19N/mm2, find maximum direct stress that can be found at this point in any possible direction. Round off your answer to the nearest N/mm?. 10 N/mm2 Txy 20 N/mm2 20 N/mm? Txy 10 N/mm2
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- The state of stresses in the x and y directions at a point in a given material is shown in the figure below. If the value of the shear stress in the x-y axes Ty is 17N/mm2, find the maximum shear stress that can be found at this point in any possible direction. Round off your answer to the nearest N/mm2. 10 N/mm2 Txy 20 N/mm2 20 N/mm2 Txy 10 N/mm2The stresses shown in the figure act at a point on the free surface of a machine component. If o= 45 MPa in the direction shown, determine the normal stress oy at the point. Ox 27 MPa 30° 50 MPa O-16.3 MPa O-19.5 MPa O-22.8 MPa O-17.2 MPa O -20.5 MPaThe state of stresses in the x and y directions at a point in a given material is shown in the figure below. If the value of the shear stress in the x-y axes Ty is 11 N/mm², find the minimum direct stress that can be found at this point in any possible direction. Round off your answer to the nearest N/mm?. If the answer is negative do insert the "-" sign. 10 N/mm2 Txy 20 N/mm2 20 N/mm2 Ixy 10 N/mm2
- 2. For the state of stress shown, determine the range of value of for which the normal is equal to or less than 100 MPa and 50 MPa. stress x' + 90 MPa 60 MPa =3. An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in the figure. Axial loads are applied at the positions indicated. Find the maximum value of P that will not exceed a stress in steel of 140 MPa, in aluminum of 13.05 ksi, or in bronze of 100 MPа. Aluminum A = 400 mm? Bronze A = 200 mm Steel A = 500 mm? 2P 4D 2.5 m 2.0 m 1.5 mThe stress concentration occurs whenever there is an abrupt change in the cross-section of a component or there is any discontinuity in the material. The figure given below shows a flat plate with a hole of diameter d. The plate is fixed at one end and the other end is subjected to a tensile load of P = 44 kN due to which there is a change in length of 0.4 mm. The thickness of the plate is 11.5 mm. The maximum stress developed in the flat plate is 228 MPa. Take Young's modulus(E) = 210 GPa and theoretical stress concentration factor =2, Calculate the following values: i) Width of the plate (W2) in mm ( ii) Nominal Stress in MPa ( iii) Diameter of the hole (d) in mm
- 1.16 The stress-strain relationship shown in Figure P1.16 was obtained during the tensile test of an aluminum alloy specimen. 60,000 H Stress, psi 40,000 20,000 0 Figure P1.16 0.002 0.004 0.006 0.008 Strain, in./in. Determine the following: a. Young's modulus within the linear portion. b. Tangent modulus at a stress of 45,000 psi c. Yield stress using an offset of 0.002 strain d. If the yield stress in part c is considered failure stress, what is the maximum working stress to be applied to this material if a factor of safety of 1.5 is used? 43 - A strain gauge is attached to the side of a beam, as shown by the cross-section view in the figure. When the beam is subjected to a specified uniform moment, the longitudinal strain measured by the gauge is -300μ. Plot the axial stress profile over the height of the cross- section. What is the magnitude of the moment that produced this strain gauge reading? Assume E = 75 GPa. 10↑ Strain gauge dimensions in mm 30 30 beamcross-sectionConsider the state of stress as shown in figure. What will be the principal stresses? 02= 16Mpa oy= – 48 M pa, Try = 60 Mpa T 48 Mpa + 16 Mpa 60 Mpa
- Q.3: A steel rod with a cross sectional area of 150 mm² is stretched between two fixed points. The tensile load at 20°C is 5000 N. a) What will be the stress at -20°C. b) At what temperature will the stress be zero? Assume a-11.7 μm/m . °C and E= 200 GPa?The stress concentration occurs whenever there is an abrupt change in the cross-section of a component or there is any discontinuity in the material. The figure given below shows a flat plate with a hole of diameter d. The plate is fixed at one end and the other end is subjected to a tensile load of P = 41 kN due to which there is a change in length of 0.4 mm. The thickness of the plate is 11 mm. The maximum stress developed in the flat plate is 235 MPa. Take Young's modulus(E) = 210 GPa and theoretical stress concentration factor =2, Calculate the following values: i) Width of the plate (W2) in mm ii) Nominal Stress in MPa iii) Diameter of the hole (d) in mm Hole with stress concentration factor 2 35 mm W2 35 mm P 300 mm 350 mm- 250 mmIf the angle of obliquity for the resultant stress at a plane which is 45° from the principal stress is 30° as shown in the figure then find the ratio of stress in x-direction to stress in y-direction. A-3.73 B 3.73 C 1.73 6² D 0.268 Correct Option B # 45%