The specific rotation of (S)-2-butanol is +135 IF100 g of its enantiomer is dissolved in 100 ml of ethanol and placed in a sample cell with a length of 1.00 dm, what observed rotation do you expect? 0 (-13.5N0.100g/mL(1.00dm) --135 O (13.510 100g/m(1.00dm] = 135 0 (-135/10.100gml}{1.00dm] = -135 O (135)0.100g/mL(1.00dm) 135
The specific rotation of (S)-2-butanol is +135 IF100 g of its enantiomer is dissolved in 100 ml of ethanol and placed in a sample cell with a length of 1.00 dm, what observed rotation do you expect? 0 (-13.5N0.100g/mL(1.00dm) --135 O (13.510 100g/m(1.00dm] = 135 0 (-135/10.100gml}{1.00dm] = -135 O (135)0.100g/mL(1.00dm) 135
Chapter4: Organic Compounds: Cycloalkanes And Their Stereochemistry
Section4.4: Conformations Of Cycloalkanes
Problem 10P
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![The specific rotation of (S)-2-butanol is +135 If 1.00 g of its enantiomer is dissolved in 100 mL of ethanol and placed in a sample cell
with a length of 1.00 dm, what observed rotation do you expect?
0(-13.5(0.100g/mL(1.00dm) --135
O (13.5)/(0.100g/m)(100dm) = 135
0(-13.5/10.100gm(1.00dm]= -135
O (13.5)(0.100g/mL)(1.00dm) 135](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F33359029-125f-4134-8c96-33c25be7a6ef%2Fbcc24127-06cc-4ea5-b864-e025a71cedcf%2Fm7itm0p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The specific rotation of (S)-2-butanol is +135 If 1.00 g of its enantiomer is dissolved in 100 mL of ethanol and placed in a sample cell
with a length of 1.00 dm, what observed rotation do you expect?
0(-13.5(0.100g/mL(1.00dm) --135
O (13.5)/(0.100g/m)(100dm) = 135
0(-13.5/10.100gm(1.00dm]= -135
O (13.5)(0.100g/mL)(1.00dm) 135
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