The span of an overhead line is 220 m, weight of conductor is 604 kg/km and ultimate tensile strength is 5758 kg. For the safety factor 2, the sag of the line will be (a) 3 m (b) 2 m (c) 1.5 m Jo1.27 m
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- Find the GMR of this conductor as r.( Need handwritten solution only please otherwise downvote)Single core cable design for 25 kV. The radius of conductor is 0.5 cm. The insulation material consists of two layers. The thickness of each layer is 2 cm. The voltage of first and second layers are 20 kV, 5 kV respectively. The minimum Electric stress of the cable is * 9.45 kV/cm 1.89 kV /cm O 1.25 kV/cm 5.78 kV/cm Non of themSingle core cable design for 25 kV. The radius of conductor is 0.5 cm. The insulation material consists of two layers. The thickness of each layer is 2 cm. The voltage of first and second layers are 20 kV, 5 kV respectively. The maximum Electric stress of the cable is
- Single core cable design for 25 kV. The radius of conductor is 0.5 cm. The insulation material consists of two layers. The thickness of each layer is 2 cm. The voltage of first and second layers are 20 kV, 5 kV respectively. The minimum Electric stress of the cable isProblem #1 • An overhead line has span of 260m. The tension in the line is 1200kg while the conductor weighs 650 kg per 100 meters. Calculate the maximum SAG in the conductor. If the height of the tower is 13 meters, estimate the clearance of conductor to the ground. Draw a figure and mark values of sag, clearance, span, height of conductor etc.33 kv single core cable has a radius of conductor of 0.6 cm. The insulation martial has two layers. The thickness of the first and second layers are 0.8 cm and 0.4 cm respectively. The relative permittivity of the first and second layers are 4 and 3 respectively. Find 3- The minimum electric stress of the second layer. 4- The minimum electric stress of the first layer.
- Q1: A single core 66 kV cable working on three phase system has a conductor diameter of 2 cm and a sheath of inside diameter 5.3 cm, if two intersheaths are introduced in such a way that the stress varies between the same maximum and minimum in the three layers, find (a)positions of intersheaths (b)voltage in the intersheaths (c)maximum and minimum stress.a.Why does power plants have high amounts of voltages? Explain. b.Is it safe for transmission lines to have high current instead of high voltage? Why? c.What phenomenon is avoided by having separations between three conductor phases? Explain this phenomenon.A single phase 2 conductor operates at 50Hz, the diameter of each condcutor is 60mm and spacing between condcutor is 5m, find the loop inductance of the line.
- Alumoweld is an aluminum-clad steel conductor. True FalseFor the case of double-circuit, bundle-conductor lines, the same method indicated in Problem 4.27 applies with r' replaced by the bundles GMR in the calculation of the overall GMR. Now consider a double-circuit configuration shown in Figure 4.36 that belongs to a 500-kV, three-phase line with bundle conductors of three subconductors at 21 in. spacing. The GMR of each subconductor is given to be 0.0485 ft. Determine the inductive reactance of the line in ohms per mile per phase. You may use XL=0.2794logGMDGMR/mi/phaseFigure 4.34 shows double-circuit conductors' relative positions in segment I of transposition of a completely transposed three-phase overhead transmission line. The inductance is given by L=2107lnGMDGMRH/m/phase Where GMD=(DABeqDBCeqDACeq)1/3 With mean distances defined by equivalent spacings DABeq=(D12D12D12D12)1/4DBCeq=(D23D23D23D13)1/4DACeq=(D13D13D13)1/4 And GMR=[ (GMR)A(GMR)B(GMR)C ]1/3 with phase GMRs defined by (GMR)A=[ rD11 ]1/2;(GMR)B=[ rD22 ]1/2;(GMR)C=[ rD33 ]1/2 and r is the GMR of phase conductors. Now consider a 345-kV, three-phase, double-circuit line with phase-conductors GMR of 0.0588 ft and the horizontal conductor configuration shown in Figure 4.35. Determine the inductance per meter per phase in Henries (H). Calculate the inductance of just one circuit and then divide by 2 to obtain the inductance of the double circuit.