The recursive call in the following method is ____________________. int factorial(int n) { if(n <= 1) return 1; else return(n * factorial(n-1)); }
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The recursive call in the following method is ____________________.
int factorial(int n)
{
if(n <= 1)
return 1;
else
return(n * factorial(n-1));
}
Step by step
Solved in 2 steps
- in java Integer numVals is read from input and integer array userCounts is declared with size numVals. Then, numVals integers are read from input and stored into userCounts. If the first element is less than the last element, then assign Boolean firstSmaller with true. Otherwise, assign firstSmaller with false. Ex: If the input is: 5 40 22 41 84 77 then the output is: First element is less than last element 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 import java.util.Scanner; public class UserTracker { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intnumVals; int[] userCounts; inti; booleanfirstSmaller; numVals=scnr.nextInt(); userCounts=newint[numVals]; for (i=0; i<userCounts.length; ++i) { userCounts[i] =scnr.nextInt(); } /* Your code goes here */ if (firstSmaller) { System.out.println("First element is less than last element"); } else { System.out.println("First element is not less…a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?Demonstrate your understanding of recursion by creating a recursive method of your own. Start with the recursive method outline below: int recurs (__________){ if (__________) return __________; // stopping base case else return __________; // recursive call} Fill in the blanks to create your own original recursive method. Post your method code. Then demonstrate a call to your recursive method that requires the method to call itself at least twice before the stopping case is encountered. For each pass (call) show: The values for the parameters of the call, going forward What values are passed back from the call, going back
- Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digitSample Data : 453211145322224532714246813579Sample Output : 23540 I want a code class and a runner class without the scanner classLab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digitSample Data : 453211145322224532714246813579Sample Output : 23540 I want a code class and a runner classjava Write a recursive method largestDigitthat accepts an integer parameter and returns the largest digit value that appears in that integer. Your method should work for both positive and negative numbers. If a number contains only a single digit, that digit's value is by definition the largest. The following table shows several example calls: Call Value Returned largestDigit(14263203) 6 largestDigit(845) 8 largestDigit(52649) 9 largestDigit(3) 3 largestDigit(0) 0 largestDigit(-573026) 7 largestDigit(-2) 2 Obey the following restrictions in your solution: You may not use a String, Scanner, array, or any data structure (list, stack, map, etc.). Your method must be recursive and not use any loops (for, while, etc.). Your solution should run in no worse than O(N) time, where N is the number of digits in the number.
- An iterative method is sometimes better than a recursive method because _______________.a. calling a function causes overheadsb. it is easy to understandc. recursion takes more memory and processing powerd. Both a. and c.Write java code that recursively calculates the Sum of the array cells. Program requirements: Create an array named MyArr and initialize it as follow: 243 88 31 19 27 81 100 6 10 5 1- Write a method named ArrSum that recursively calculates the Sum of the numbers in the Array and returns the Sum of the numbers. Hint: Method with 1 parameter (the Array) that returns 1 value (the Array's Sum). 2- Write a method named Display that displays the Array contents and Sum of the numbers. Hint: Method with 2 parameters (the Array) and Sum with no returns (void) 3- Write a method named ArrSort using the bubble sort to sort Array. 4- Your program output format must be the same as the following: =>> Array Summation Array: 5 6 10 19 27 31 81 88 100 243 Sum: 610 =>> End of the Program Be sure to add Documentation / CommentsIn Java, recursion can be used to solve different problems such as factorial of a given number. ___________________ implies 5 x 4 x 3 x 2 x 1.
- JAVA program Write a Java program that asks the user to enter an array of integers. The program should prompt the user for the number of elements in the array and then the elements of the array. The program should then call a method named minGap that accepts the array entered by the user as a parameter and returns the minimum 'gap' between adjacent values in the array. The main method should then print the value returned by the method. The gap between two adjacent values in an array is defined as the difference in value between the first element and the second element. For example, suppose the user entered the following array of integers {1, 3, 6, 5, 12} The first gap is 2 (3 - 1), the second gap is 3 (6 - 3), the third gap is 1 (6 - 5) and the fourth gap is 5 (12 - 6). Thus, the call of minGap(array) should return 1 because that is the smallest gap in the array. If you are passed an array with fewer than 2 elements, you should return 0. Use Math.abs()JAVA Question 2: For two integers m and n, their GCD (Greatest Common Divisor) can be computed by a recursive method. Write a recursive method gcd(m,n) to find their Greatest Common Divisor. Method body: If m is 0, the method returns n. If n is 0, the method returns m. If neither is 0, the method can recursively calculate the Greatest Common Divisor with two smaller parameters: One is n, the second one is m mod n (or m % n). The recursive method cannot have loops. Note: although there are other approaches to calculate Greatest Common Divisor, please follow the instructions in this question, otherwise you will not get the credit. main method: Prompt and read in two numbers to find the greatest common divisor. Call the gcd method with the two numbers as its argument. Print the result to the monitor. Example program run: Enter m: 12 Enter n: 28 GCD(12,28) = 4 And here is what I have so far, package CSCI1302;import java.util.*;public class RecursionDemo { public static void…JAVA program Write a Java program that asks the user to enter an array of integers. The program should prompt the user for the number of elements in the array and then the elements of the array. The program should then call a method named minGap that accepts the array entered by the user as a parameter and returns the minimum 'gap' between adjacent values in the array. The main method should then print the value returned by the method. The gap between two adjacent values in an array is defined as the difference in value between the first element and the second element. For example, suppose the user entered the following array of integers {1, 3, 6, 5, 12} The first gap is 2 (3 - 1), the second gap is 3 (6 - 3), the third gap is 1 (6 - 5) and the fourth gap is 5 (12 - 6). Thus, the call of minGap(array) should return 1 because that is the smallest gap in the array. If you are passed an array with fewer than 2 elements, you should return 0.