The physical address of the following memory location specified in the instruction MOV [BX-0200H], AL i . . (assume SS=5000H, DS=6000H, * ES=7000H, BX=1000H, AL=10H) 51200H O 71210H O 61210H O 61200H O 71200H O
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![The physical address of the following memory location specified in the
instruction MOV [BX-0200H], AL i .
. (assume SS=5000H, DS=6000H,
* ES=7000H, BX=1000H, AL=10H)
51200H O
71210H O
61210H O
61200H O
71200H O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9b2d7f1c-5726-4cd5-bac1-2a708caf71b0%2F0e7a18da-62b1-46de-9f65-83b5e51a9f95%2Fkpw2jnb.png&w=3840&q=75)
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- Memory address Data According to the memory view given below, if RO = Ox20008002 then LDRSB r1, [r0, #-4] is executed as a result of r1 = ?(data overlay big endian)? Øx20008002 ØXA1 Øx20008001 ØXB2 Øx20008000 Øx73 ØX20007FFE ØXD4 ØX20007FFE Lütfen birini seçin: O A. R1 = 0X7F O B. R1 = Oxffffffd4 O C. R1 = Oxffffff7F O D. R1=0XD4000000 O E. R1 = 0XD4The memory location at address of 0X003FB01 contains 1-byte memory variable J (0010_0001), and the memory location at the address of 0X003FB02 contains 1-byte memory variable K (0001 0010), see figure below. There is a 2-byte variable M which hold binary information M (1110 0101 0000 1i11). What is the address in hexadecimal format for 2-byte memory variable M, following little Endian computer? 7 Address in Data in Hex. Format Hex. Format 0X003FBF04 1110 0101 M OX003FBF03 0000 1111 0X003FBF02 0001 0010 0X003FBF01 0010 0001 J Its address in hexadecimal is 0X003FBF02. а. Its address in hexadecimal is 0×003FBF03. O b. Its address in hexadecimal is 0X003FBF04. Its address in hexadecimal is 0×003FBF01. d.Consider the array : char arr[5]; If address of arr is 100 then what will be the address of arr[4]. Given each char occupies 1 byte in a byte addressable system.
- Given the image below, what is the Linear Address of the memory location currently being pointed to in the Data Segment . Make all hexadecimal letters lower case ● Use no spaces in your answer You may proceed the answer by Ox if you like (lower case x) Do not include leading zeros (in the most significant nibbles) in your answer Segment Descriptor Table ??? 19 0x1A0020 0x0224 20 0x2B0020 ??? 21 0x000F5B OXOA 22 0x09223A 23 0x09223A CS 0022 DS 0019Given rax = 0x0000000200000100, rbx = 0x0000000000000100, and rcx = 0x0000000000000001,and the following values in memoryaddress -> byte at that address0x0000000000000100 -> 0x010x0000000000000101 -> 0x000x0000000000000102 -> 0x000x0000000000000103 -> 0x000x0000000000000104 -> 0x020x0000000000000105 -> 0x000x0000000000000106 -> 0x000x0000000000000107 -> 0x00what is the new value in %rax after the following operation?subq -0x04(%rbx, %rcx, 4), %raxConsider the following table that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): ADDRESS OxFFFF OXOCOE OXOCOD Ox0C0C OXOCOB OXOCOA 0x0C09 0x0000 CONTENTS 1111 1111 1111 1111 1111 1110 1101 1100 0001 1011 1100 0101 0110 0101 1000 0111 1100 0000 0100 0000 0011 0001 0101 0010 0000 1100 0000 1101 0000 0000 0000 0000 The table above shows the addresses in hex (base 16) and the contents at the corresponding address in binary (base 2). A.) What are the contents in hex of the memory location at following address in binary: 0000 1100 0000 1110? (Enter hex like the following example: Ox2A3F)
- Let's say that p is a pointer to memory and the next six bytes in memory (in hex) beginning at p's address are: aa bb cc dd ee ff. What value would be in x if the following code is run on a little- endian computer? uint16_t *q uint16_t x = (uint16_t *)p; q[0]; aa aabb bbaa aabbccdd ddccbbaaThe table below shows a segment of primary memory from a Von Neumann model computer Address Data 10101000 10001000 11001000 10011001 10100000 10101010 10110100 10111011 10001100 11001100 The program counter (PC) contains a value of 11001000. Find the value (in binary) that will be placed in MAR (memory address register)? MAR (in binray) %3D Find the value (in binary) that will be placed in MBR (memory buffer register)? MBR = (binray) %3D3. Calculate the physical memory location for each of the following cases? a- The logical address D470H in the extra segment. b- The logical address 2D90H in the stack segment. C- MOV [BP],AL if BP=2C30H. Assume ES=52B9, SS=5D27, DS=E000, and CS=B3FF.
- Show the content of the individual bytes allocated in memory in hexadecimal for the following declarations. Assuming that the address of I is 404000h, what are the addresses of J, K, and L? What is the total number of allocated bytes?According to the memory view given below, if RO = 0x20008000, then LDRSB r1, r1 = ?(data overlay big endian)? Memory address Data Øx20008002 ØXA1 Øx20008001 ØXB2 Øx20008000 ØxC3 ØX20007FFE ØXD4 ØX20007FFE OXE5 (Ctrl) A-R1 = 0XC3 B-R1 = 0x000000C3 C-R1 = OXC3000000 D-R1 = 0xffffffC3 E-R1 = OxC3ffffffConsider the following image that represents part of the memory of a 16-bit address space that has an addressability of 2 bytes (like LC-3): A memory location can store an address. We call that memory location's contents a "pointer" since it's an address that "points" to another memory location. G.) Interpret the contents at address 0x0C0B as a pointer. (Enter hex like the following example: 0x2A3F) H.) What are the contents of the memory location that the pointer above is pointing to? (Enter hex like the following example: 0x2A3F) Another reference : LC-3 Opcodes in Hex ADD 0x1 JMP 0xC LDR 0x6