The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 3.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 19 in. is the length of the bar, and E = 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.13P: An clement of material in plane strain (see figure) is subjected to strains ex= 480 × 10-6, Ey= 70 ×...
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The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where
y = 2.4 lb/in.³ is the specific weight of the material, y = 3.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 19 in. is the
length of the bar, and E= 24000 ksi is a material constant. Determine,
(a) the change in length of the bar due to its own weight.
(b) the average normal strain over the length L of the bar.
(c) the maximum normal strain in the bar.
Part 1
Calculate the change in length of the bar due to its own weight.
Answer:
d = i
x10-6 in.
Transcribed Image Text:The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression vy/3E where y = 2.4 lb/in.³ is the specific weight of the material, y = 3.8 in. is the distance from the free (i.e., bottom) end of the bar, L = 19 in. is the length of the bar, and E= 24000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar. (c) the maximum normal strain in the bar. Part 1 Calculate the change in length of the bar due to its own weight. Answer: d = i x10-6 in.
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