The most appropriate name for the structure is: HO H₂C |||** H₂C H H CH₂ (2S, 6S, 7Z)-6-methyl-non-7-en-4-yn-2-ol (2R, 6R, 7E)-6-methyl-non-7-en-4-yn-2-ol (2R, 6S, 7E)-6-methyl-non-7-en-4-yn-2-ol (2S, 6R, 7Z)-6-methyl-non-7-en-4-yn-2-ol
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- Please convert this name into the structure: (2R,3R,4S,5S,6R)-2-(((2S,3S,4S,5R)-3,4-dihydroxy-2,5-bis(hydroxymethyl)tetrahydrofuran-2-yl)oxy)-6-(hydroxymethyl)tetrahydro-2H-pyran-3,4,5-triolProvide a name for the following compound Br O 2-Bromo-4-chloro-4-isopropylpentane 4-Bromo-2-chloro-2-isopropylpentane 5-Bromo-3-chloro-2,3-dimethylhexane O 2-Bromo-4-chloro-4,5-dimethylhexane 2-(2-Bromopropyl)-2-chloro-3-methylbutaneThe name for the following compound is CH, H,C (2R)-3-methyl-5-hexen-3-ol (2S)-3-methyl-5-hexen-3-ol O (BR)-3-methyl-5-hexen-3-ol (3S)-3-methyl-5-hexen-3-ol
- Part B: Draw the structures for the following names: 4-cyclopropyl-2-methyl-3-nitrohept-6-yne-1-ol 4-phenyl-2-propoxy-3-hexanone 4-chloropentyl cis-2,3-dimethyl-2-hexenoate N,N-dimethyl-1-aminopent-2-yneDraw the structure of the following compounds: [(1E,3E)-hexa-1,3-dien-1-yl]cyclopentane 2-hydroxycyclopentanone 2-methylpentan-2-ol 1,2-diethyl-3-flourobenzeneFrom : cis (1s, 4s) -1-bromo- (tert-butyl) cyclohexane trans (1r, 4r)- 1- iodo- 4- isoproppylcyclohexane 1,5 - dimethylcyclohex -1 -ene trans (1r, 4r)- (tert - butyl) - 4- fluorocyclohexane trans (1r, 4r) - 1- bromo - 4- (tert - butyl) cyclohexane 1,3,5 - trimethylcyclohex - 1- ene . 5- Choose the substrate from the ones that drawn and illustrate an example complete Markovnikov addition mechanism using the reagents of your choice showing all stereochemical consequences. Identify if your addition mechanism is syn addition or anti addiction (Use curved arrows to show the electron movement in everyday steps). use ChemDraw if possible..
- What is an appropriate systematic name for the following? OH (R)-(1-methyl-2-hydroxypropyl)cyclopentane (2R,3R)-2-cyclopentylbutan-3-ol (2R,3R)-3-cyclopentylbutan-2-ol (2R,3R)-3-cyclopropylbutan-2-olDraw the structure of the alkene with the molecular formula CH10 that reacts with Br, to give this compound. CH3 Br Br • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. opyste ot pt pt pt ptSeveral diamines are building blocks for the synthesis of pharmaceuticals and agro- chemicals. Show how both 1,3-propanediamine and 1,4-butanediamine can be pre- pared from acrylonitrile. NH2 H,N `NH2 H,N CH,=CH-C=N 1,3-Propanediamine 1,4-Butanediamine Acrylonitrile
- What are the starting reactants for the following reaction? 4 X = cyclohexa-1,3-diene; Y = ethyl acrylate X = cyclopenta-1,3-diene; Y = acrylaldehyde X = cyclohexa-1,3-ene; Y = ethyl acrylate X = hexa-1,3-diene; Y = ethyl propiolate CO₂C₂H5Indicate the products of the reaction with their name and stereochemistry: Å CH₂ CH3 C6H5 H₂O, H+Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new p bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What are the structures of A, B, and C?