The magnitude of the electric field of an electromagnetic wave in a vacuum is |E,| = (20.0 ) sin((6.30 × 10®)x – (1.90 × 10'7)t). where x is in meters and t is in seconds. i) What is the wavenumber of the wave? m A. 3.31 x 10-17 ii) What is the frequency of the wave? Hz B. 9.97x 10-9 iii) What is the amplitude of the wave? N/C C. 20.0 D. 1.00 x 10B iv) If the electric field is directed up the page and the wave is propagating out of the page, then what must be the direction of the magnetic field? E. 6.30 x 10 F. 3.02 x 1016 G. 1.90 x 1017 SHORT ANSWER Direction of magnetic field:
The magnitude of the electric field of an electromagnetic wave in a vacuum is |E,| = (20.0 ) sin((6.30 × 10®)x – (1.90 × 10'7)t). where x is in meters and t is in seconds. i) What is the wavenumber of the wave? m A. 3.31 x 10-17 ii) What is the frequency of the wave? Hz B. 9.97x 10-9 iii) What is the amplitude of the wave? N/C C. 20.0 D. 1.00 x 10B iv) If the electric field is directed up the page and the wave is propagating out of the page, then what must be the direction of the magnetic field? E. 6.30 x 10 F. 3.02 x 1016 G. 1.90 x 1017 SHORT ANSWER Direction of magnetic field:
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter16: Waves
Section: Chapter Questions
Problem 43P: (a) Seismographs measure the arrival times of earthquakes with a precision of 0.100 s. To get the...
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