The magnitude of the electric field of an electromagnetic wave in a vacuum is |E,| = (20.0 ) sin((6.30 × 10®)x – (1.90 × 10'7)t). where x is in meters and t is in seconds. i) What is the wavenumber of the wave? m A. 3.31 x 10-17 ii) What is the frequency of the wave? Hz B. 9.97x 10-9 iii) What is the amplitude of the wave? N/C C. 20.0 D. 1.00 x 10B iv) If the electric field is directed up the page and the wave is propagating out of the page, then what must be the direction of the magnetic field? E. 6.30 x 10 F. 3.02 x 1016 G. 1.90 x 1017 SHORT ANSWER Direction of magnetic field:

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Chapter16: Waves
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a)
The magnitude of the electric field of an electromagnetic wave in a vacuum is
JE = (20.0 ) sin((6.30 × 10ª)x – (1.90 × 10'7)t),
where x is in meters andt is in seconds.
i)
What is the wavenumber of the wave?
m
A. 3.31 x 10-17
ii)
What is the frequency of the wave?
Hz
B. 9.97x 10-9
ii)
What is the amplitude of the wave?
N/C
С. 20.0
D. 1.00 x 108
iv)
If the electric field is directed up the page and the wave is
propagating out of the page, then what must be the direction
of the magnetic field?
E. 6.30 x 10
F. 3.02 x 1016
G. 1.90 x 1017
SHORT ANSWER
Direction of magnetic field:
= 自2
Transcribed Image Text:a) The magnitude of the electric field of an electromagnetic wave in a vacuum is JE = (20.0 ) sin((6.30 × 10ª)x – (1.90 × 10'7)t), where x is in meters andt is in seconds. i) What is the wavenumber of the wave? m A. 3.31 x 10-17 ii) What is the frequency of the wave? Hz B. 9.97x 10-9 ii) What is the amplitude of the wave? N/C С. 20.0 D. 1.00 x 108 iv) If the electric field is directed up the page and the wave is propagating out of the page, then what must be the direction of the magnetic field? E. 6.30 x 10 F. 3.02 x 1016 G. 1.90 x 1017 SHORT ANSWER Direction of magnetic field: = 自2
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