The issue: Unexpected events can occur as a result of parameterized expressions. Suppose the following scenario: #define SQUARE(x) ((x) * (x)) int i = 5; int j = SQUARE(i++); What does j stand for? It depends on the programmer, is the response. Additionally, i's worth is unquestionably not 6. Why? Observe the text after the macro has been expanded: int j = ((i++) * (i++)); This demonstrates that i is incremented twice. The exact value of j is also contingent on the compiler because the C++ standard does not specify the order of the operations.
The issue: Unexpected events can occur as a result of parameterized expressions. Suppose the following scenario: #define SQUARE(x) ((x) * (x)) int i = 5; int j = SQUARE(i++); What does j stand for? It depends on the programmer, is the response. Additionally, i's worth is unquestionably not 6. Why? Observe the text after the macro has been expanded: int j = ((i++) * (i++)); This demonstrates that i is incremented twice. The exact value of j is also contingent on the compiler because the C++ standard does not specify the order of the operations.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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The issue: Unexpected events can occur as a result of parameterized expressions. Suppose the following scenario:
#define SQUARE(x) ((x) * (x))
int i = 5;
int j = SQUARE(i++);
What does j stand for? It depends on the programmer, is the response. Additionally, i's worth is unquestionably not 6. Why? Observe the text after the macro has been expanded:
int j = ((i++) * (i++));
This demonstrates that i is incremented twice. The exact value of j is also contingent on the compiler because the C++ standard does not specify the order of the operations.
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