The image of AABC after a reflection across ÈG Which triangle must be a right triangle and why? s ΔΑ'Β'C'. AA'B'C' is right because it is the image of AABO AADC is right because AA' intersects AC at A. ABCC' is right because B lies of the line of B B' reflection. A' F D ABGC is right because EG 1 CC. A C' G

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Q: (Picture of question is attached)

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Q: cos 2z dz, C the semicircle |z| = 7, x2 0 from - πί to πί

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Q: 25-r2 Evaluate (x2 + y?)3 dy dx by converting to polar coordinates.

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Q: 2.lexPress the faiauing curve inthe form of Yara meter eQuation al Y=1-×モン-2 b.) y? zzg,x>4

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Q: 5. Consider the two curves r= / cos(0) and r= V2 cos(0), -T/2<0ST/2,whose polar plo 0.6 0.4 0.2 0.2…

A: Here, the given curves are: r=cos θ &amp; r=2cos θ

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Q: 2y )dx - (x +3 cos y)dy around the parallelogram havi - 6

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Q: 3IZ 21 C 2 3 3 y

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Q: 3) Use polar coordinate to evaluate S'S_√x² + y² dxdy.

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Q: jw F(w). 2 - TAN [* - ACOS(WT)] acos Tjw jw F(W) = -2A (₁ - cos (WT)). Tjw jWF(W) = -2A (asin" (WI))…

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differential equations.