The H-NMR spectrum of compound B, C7H140, consists of the following signals: 80.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B. • You do not have to consider stereochemistry. • Explicitly draw all H atoms. .

The H-NMR spectrum of compound B, C7H140, consists of the following signals: 80.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H). Draw the structural formula of compound B. • You do not have to consider stereochemistry. • Explicitly draw all H atoms. .

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter13: Nuclear Magnetic Resonance Spectroscopy

Section: Chapter Questions

Problem 13.27P: The 13C-NMR spectrum of 3-methyl-2-butanol shows signals at 17.88 (CH3), 18.16 (CH3), 20.01 (CH3),...

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

) The H-NMR spectrum of compound B, C7H₁4 O, consists of the following signals: 8 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t,
4H).
Draw the structural formula of compound B.
.
You do not have to consider stereochemistry.
Explicitly draw all H atoms.
.

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