The H NMR spectra corresponds to a hydrocarbon with the molecular formula C6H₁4. Deduce the structure fromthe spectra.Draw the unknown compound.'H NMR12 HSelectDrawRingsMore1.5 1.42 H1.5 1.0 0.5 0.0300-MHz H NMRspectrum ppm (8)0.9 0.8(CH3)4SiGGQ2E

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The H NMR spectra corresponds to a hydrocarbon with the molecular formula C6H₁4. Deduce the structure from the spectra. 'H NMR Draw the unknown compound. 12 H Select Draw Rings More A 1.5 1.4 2 H 1.5 1.0 0.5 0.0 300-MHz H NMR spectrum ppm (8) 0.9 0.8 (CH3)4Si G C+ Q2E

The H NMR spectra corresponds to a hydrocarbon with the molecular formula C6H₁4. Deduce the structure from the spectra. 'H NMR Draw the unknown compound. 12 H Select Draw Rings More A 1.5 1.4 2 H 1.5 1.0 0.5 0.0 300-MHz H NMR spectrum ppm (8) 0.9 0.8 (CH3)4Si G C+ Q2E

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter18: Ethers And Epoxides; Thiols And Sulfides

Section18.9: Spectroscopy Of Ethers

Problem 18P: The 1H NMR spectrum shown is that of a cyclic ether with the formula C4H8O. Propose a structure.

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Concept explainers

NMR Spectroscopy

NMR stands for Nuclear Magnetic Resonance in which the study of different molecules is done based on the interaction of radiofrequency electromagnetic radiations with the nuclei of molecules placed in a strong magnetic field. A precise study of spectra of visible light and all bands of electromagnetic radiation is called spectroscopy.

Question

The H NMR spectra corresponds to a hydrocarbon with the molecular formula C6H₁4. Deduce the structure from
the spectra.
Draw the unknown compound.
'H NMR
12 H
Select
Draw
Rings
More
1.5 1.4
2 H
1.5 1.0 0.5 0.0
300-MHz H NMR
spectrum ppm (8)
0.9 0.8
(CH3)4Si
G
G
Q2E

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