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The graph of y = f'(x) is shown below. Assume the domain of ƒ(x) and ƒ'(x) are both ( − ∞0, -5 -4 -3 -2 -1 5 4 3 -2 -3 -4 2 Remember this is the graph of y = f'(x), not the graph of y = f(x) Based on this graph: y = f(x) is increasing on the interval(s) y = f(x) is decreasing on the interval(s) Therefore f(x) has a max at x = y = f(x) is concave up on the interval(s) y = f(x) is concave down on the interval(s) Therefore f(x) has inflection point(s) at x = and a local min at x =

The graph of y = f'(x) is shown below. Assume the domain of ƒ(x) and ƒ'(x) are both ( − ∞0, -5 -4 -3 -2 -1 5 4 3 -2 -3 -4 2 Remember this is the graph of y = f'(x), not the graph of y = f(x) Based on this graph: y = f(x) is increasing on the interval(s) y = f(x) is decreasing on the interval(s) Therefore f(x) has a max at x = y = f(x) is concave up on the interval(s) y = f(x) is concave down on the interval(s) Therefore f(x) has inflection point(s) at x = and a local min at x =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 41E
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The graph of y = f'(x) is shown below. Assume the domain of ƒ(x) and ƒ'(x) are both ( − ∞, ∞). -5 -4 -3 -2 -1 5+ 4 3 T -1 -2 -3 -4 -5- 1 2 4 Remember this is the graph of y = f'(x), not the graph of y = f(x) Based on this graph: y = f(x) is increasing on the interval(s) y = f(x) is decreasing on the interval(s) Therefore f(x) has a max at x = y = f(x) is concave up on the interval(s) y = f(x) is concave down on the interval(s) Therefore f(x) has inflection point(s) at x = and a local min at x =
Transcribed Image Text:The graph of y = f'(x) is shown below. Assume the domain of ƒ(x) and ƒ'(x) are both ( − ∞, ∞). -5 -4 -3 -2 -1 5+ 4 3 T -1 -2 -3 -4 -5- 1 2 4 Remember this is the graph of y = f'(x), not the graph of y = f(x) Based on this graph: y = f(x) is increasing on the interval(s) y = f(x) is decreasing on the interval(s) Therefore f(x) has a max at x = y = f(x) is concave up on the interval(s) y = f(x) is concave down on the interval(s) Therefore f(x) has inflection point(s) at x = and a local min at x =
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