The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented by two. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base:: failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 20 Lua 23 Mary 0 Stu 35

The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented by two. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base:: failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 20 Lua 23 Mary 0 Stu 35

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 5PE

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The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 main.cpp #include <string>#include <iostream> using namespace std; int main(int argc, char* argv[]) {string inputName;int age;// Set exception mask for cin streamcin.exceptions(ios::failbit); cin >> inputName;while(inputName != "-1") {// FIXME: The following line will throw an ios_base::failure.// Insert a try/catch statement to catch the exception.// Clear cin's failbit to put cin in a useable state.cin >> age;cout << inputName << " " << (age + 1) << endl; cin >> inputName;}return 0;}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34
. The TryParse methods throw an exception if the string argument cannot be converted
s and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 419894.2696446.qx3zqy7 #include <string>#include <iostream> using namespace std; int main() { string inputName; int age; // Set exception mask for cin stream cin.exceptions(ios::failbit); cin >> inputName; while(inputName != "-1") { // FIXME: The following line will throw an ios_base::failure. // Insert a try/catch statement to catch the exception. // Clear cin's failbit to put cin in a useable state. cin >> age; cout << inputName << " " << (age + 1) << endl; cin >> inputName; } return 0;}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an int. At FIXME in the code, add a try/catch statement to catch ios_base::failure, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 √
True or False The TryParse methods throw an exception if the string argument cannot be converted.
1. When does the + operator concatenate instead of add? What happens if you try to use + on a string with an integer? Why do you think this happens? 2. If a string has 10 characters, what is the index of the last character? 3. Explain why this code causes an exception: Animal = "Tiger" Animal[0] = "L"
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 NameAgeChecker.java import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker {public static void main(String[] args) {Scanner scnr = new Scanner(System.in); String inputName;int age;inputName = scnr.next();while (!inputName.equals("-1")) {// FIXME: The following line will throw an InputMismatchException.// Insert a try/catch statement to catch the exception.age = scnr.nextInt();System.out.println(inputName + " " + (age + 1));inputName = scnr.next();}}}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 -----------This is what I need to fill out---------- # Split input into 2 parts: name and ageparts = input().split()name = parts[0]while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.age = int(parts[1]) + 1print('{} {}'.format(name, age))# Get next lineparts = input().split()name = parts[0]
Challenge 2: InvalidNumbers.java Write a program InvalidNumbers that asks the user to enter a positive integer. The program will warn the user if a valid integer is not entered using the InputMismatchException and ask to enter again. The program should also throw an exception if the user enters negative numbers. Write the program and test it using negative numbers, doubles, and very large numbers.
Java programming See attached The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a String rather than an Integer. At FIXME in the code, add a try/catch statement to catch java.util.InputMismatchException, and output 0 for the age. import java.util.Scanner;import java.util.InputMismatchException; public class NameAgeChecker { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String inputName; int age; inputName = scnr.next(); while (!inputName.equals("-1")) { // FIXME: The following line will throw an InputMismatchException. // Insert a try/catch statement to catch the exception. age = scnr.nextInt(); System.out.println(inputName + " " + (age + 1)); inputName = scnr.next(); } }}
The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age. Ex: If the input is: Lee 18 Lua 21 Mary Beth 19 Stu 33 -1 then the output is: Lee 19 Lua 22 Mary 0 Stu 34 code name = ()age = ()parts = input().split()name = parts[0]while name != '-1':# FIXME: The following line will throw ValueError exception.# Insert try/except blocks to catch the exception.age = int(parts[1]) + 1print('{} {}'.format(name, age))# Get next lineparts = input().split()name = parts[0]