The gas-phase reaction of NO with F2 to form NOF and F has an activation energy of E = 6.30 kJ/mol and a frequency factor of A = 6.00x108 M1.s-1. The reaction is believed to be bimolecular: Given that dashed lines indicate the weak bonds that are beginning to form, which is the most probable transition state for the formation of NOF? • View Available Hint(s) NO(g) +F2(g)→NOF(g) +F(g) :Ö=N: :Ö=Ñ: F-F

Chemistry
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Chapter12: Chemical Kinetics
Section: Chapter Questions
Problem 82E: The decomposition of NH3 to N2 and H2 was studied on two surfaces: Surface Ea (kJ/mol) W 163 Os 197...
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Part E
The gas-phase reaction of N0 with F2 to form
NOF and F has an activation energy of Ea = 6.30
Given that dashed lines indicate the weak bonds that are beginning to form, which is the most probable transition state for the
formation of NOF?
kJ/mol and a frequency factor of A = 6.00x108
M-1.s-1 . The reaction is believed to be
•S
• View Available Hint(s)
bimolecular:
NO(g) +F2(g)→NOF(g)+F(g)
Ö=N.
F-F
:Ö=N:
F-F
:Ö=N:
F-F
F-F
Transcribed Image Text:Part E The gas-phase reaction of N0 with F2 to form NOF and F has an activation energy of Ea = 6.30 Given that dashed lines indicate the weak bonds that are beginning to form, which is the most probable transition state for the formation of NOF? kJ/mol and a frequency factor of A = 6.00x108 M-1.s-1 . The reaction is believed to be •S • View Available Hint(s) bimolecular: NO(g) +F2(g)→NOF(g)+F(g) Ö=N. F-F :Ö=N: F-F :Ö=N: F-F F-F
Part F
Which of the following statements reasonably explains why this reaction has a low activation energy?
• View Available Hint(s)
Because this reaction is only bimolecular, the frequency of random collision is very high.
The small NO and F2 molecules have little steric hindrance; therefore random collisions occur more frequently.
The formal positive charge on the NO molecule is attracted to the formal negative charge on the F2 molecule,
so the driving force for the formation of the transition state is greater than simple random collisions.
The electron-deficient NO molecule is attracted to the electron-rich F2 molecule, so the driving force for the
formation of the transition state is greater than simple random collisions.
Transcribed Image Text:Part F Which of the following statements reasonably explains why this reaction has a low activation energy? • View Available Hint(s) Because this reaction is only bimolecular, the frequency of random collision is very high. The small NO and F2 molecules have little steric hindrance; therefore random collisions occur more frequently. The formal positive charge on the NO molecule is attracted to the formal negative charge on the F2 molecule, so the driving force for the formation of the transition state is greater than simple random collisions. The electron-deficient NO molecule is attracted to the electron-rich F2 molecule, so the driving force for the formation of the transition state is greater than simple random collisions.
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