Machine organizationWhich line sets the flag to check for end of loop? The following JAVA program is translated to LC3 assembly language.for (i=0, i<10, i++) {A[i] = 0;}The LC3 code:. ORIG x3000; RO € 0; R5 € 0RO,RO,#0R5, R5,#0R1, ADDRAR2 , MINUS10R3,R0,R2ANDANDLDLD; R2 € #-10LOOPADDBRzDONER4, R1,ROR5, R4, #0ADDSTRADDRO,RO,#1BRLOOPDONEHALTADDRA.FILL x4000.FILL #-10. ENDMINUS10

The following JAVA program is translated to LC3 assembly language. for (i=0, i<10, i++) { A[i] = 0; } The LC3 code: . ORIG x3000 AND RO,RO , #0 ; RO € 0 ; R5 € 0 AND R5,R5,#0 LD R1,ADDRA ; R2 € #-10 R2 ,MINUS10 R3,RO,R2 LD LOOP ADD BRz DONE R4,R1,RO R5,R4,#0 ADD STR ADD R0,RO,#1 BR LOOP DONE НALT ADDRA .FILL x4000 .FILL #-10 . END MINUS10

The following JAVA program is translated to LC3 assembly language. for (i=0, i<10, i++) { A[i] = 0; } The LC3 code: . ORIG x3000 AND RO,RO , #0 ; RO € 0 ; R5 € 0 AND R5,R5,#0 LD R1,ADDRA ; R2 € #-10 R2 ,MINUS10 R3,RO,R2 LD LOOP ADD BRz DONE R4,R1,RO R5,R4,#0 ADD STR ADD R0,RO,#1 BR LOOP DONE НALT ADDRA .FILL x4000 .FILL #-10 . END MINUS10

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 18RQ

See similar textbooks

Similar questions

Convert the following into Pep/9 Assembler: #include using namespace std; int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq; } int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0; }
MIPS Programming Assignment Part I Rewrite C statements int i = 11; int j = 10; int A[] = { 0x11, 0x22, 0x33 }; int B[] = { 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 }; B[ 8 ] = A[ i - j ]; in MIPS assembly. Assume that addresses of variables i, j, A, and B are loaded into the registers $s3, $s4, $s6, and $s7, respectively: .data i: .word 11 j: .word 10 A: .word 0x11, 0x22, 0x33 B: .word 0x0, 0x1, 0x2, 0x3, 0x4, 0x5, 0x6, 0x7, 0x8 .text la $s3, i # load address of i la $s4, j # load address of j la $s6, A # load address of A la $s7, B # load address of B When you finished programming, add a comment at the end of your code which specifies what value is assigned to the location of B[8] after the program executes. Part IIWrite MIPS Assembly program that allows the user to enter a string of text. Determine whether the entered string is a palindrome (a word or a phrase that reads the same backward as forward, like "kayak" and "level") and print the result on the screen.
Convert the following into Pep/9 Assembler: #include <iostream>using namespace std;int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq;}int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0;} Submit: Source file along with screen captures showing the program running in the Pep simulator.
Translate the following c++ code into pep9 assembly language #include using namespace std; int square(int n){ int i; int sq; sq = 0; for (i = 0; i < n; i++){ sq = sq + n; } return sq; } int main (){ int num; cout << "Enter a number: "; cin >> num; cout << num << " squared = " << square(num) << endl; return 0; }
IN THE C PROGRAMMING LANGUAGE j = 15; k = 9 // what are the values for n,m,and p after these operations: --j ; k++ ; n = j - ++k; m = j-- + k--; p = k + j;
Translate the following C program to Pep/9 assembly language. #include <stdio.h> int myAge; void putNext(int age) {int nextYr;nextYr = age + 1;printf("Age: %d\n", age);printf("Age next year: %d\n", nextYr);} int main () {scanf("%d", &myAge);putNext(myAge);putNext(64);return 0;}
Convert the following c++ code into pep9 assembly language #include <iostream> using namespace std; int times(int mpr, int mcand) { int prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } return prod; } int main(){ int n, m; cout << "Enter two numbers: "; cin >> n >> m; cout << "Product: " << times(n, m) << endl; return 0; } Submit: pep source code and as well as the screenshot of pep9 assembly code running in the pep stimulator.
Translate the following C program into Pep/9 assembly language:#include <stdio.h>int main () {int num1;int num2;scanf("%d", &num1);num2 = -num1;printf("num1 = %d\n", num1);printf("num2 = %d\n", num2);return 0;} please explain and provide c
Please convert to C language #include <bits/stdc++.h>using namespace std; //folding method int main(){ string s; cout << "enter number\n"; cin >> s; //folding and summing int sum = 0; for (int i = 0; i < s.length(); i += 2) { if (i + 1 < s.length()) sum += stoi(s.substr(i, 2)); else //when only one digit is left for folding sum += stoi(s.substr(i, 1)); } cout << s << "->" << sum % 10; return 0;} Output:
Please can you convert this part of a c program to pep 9 assembly language void findLog ( int *result, int num, int b ) { int k; num--; *result = 0; while (num > 0) { *result = *result + 1; num = divide(num, b); } // end while } // end of findLog( )
Translate the following C program to Pep/9 assembly language. #include int inpNum, sum, count, min; int main() { sum = 0; count = 0; min = 32767; printf("? "); scanf("%d", &inpNum); while (inpNum != 0 ) { sum += inpNum; count++; if (inpNum < min) { min = inpNum; } printf("? "); scanf("%d", &inpNum); } // end while printf("Sum printf("Count printf("Min } // end of main = = %d\n", sum); = %d\n", count); %d\n", min);
Recreate the following C program in x86-64 and aarch64 assembly manually: #include <stdio.h> typedef struct _v2d {long x;long y;} v2d_t; static long dot(v2d_t a, v2d_t b){return a.x * b.x + a.y * b.y;} static long dot_ptr(v2d_t *a, v2d_t *b){return a->x * b->x + a->y * b->y;} int main(void){v2d_t a, b; scanf("%ld %ld %ld %ld", &a.x, &a.y, &b.x, &b.y); long res1 = dot(a, b);printf("%ld\n", res1); long res2 = dot_ptr(&a, &b);printf("%ld\n", res2); return 0;}