The figure below shows a small, charged bead, with a charge of q = +42.0 nC, that moves a distance of d = 0.189 m from point A to point B in the presence of a uniform electric field  E  of magnitude 270 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the bead? magnitude Ndirection     (b) What is the work (in J) done on the bead by the electric force as it moves from A to B?  J (c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.) PEB − PEA =  J (d) What is the potential difference (in V) between A and B? VB − VA =  V

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter12: Oscillatory Motion
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The figure below shows a small, charged bead, with a charge of q = +42.0 nC, that moves a distance of d = 0.189 m from point A to point B in the presence of a uniform electric field 
E
 of magnitude 270 N/C, pointing right.
A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right.
(a)
What is the magnitude (in N) and direction of the electric force on the bead?
magnitude Ndirection    
(b)
What is the work (in J) done on the bead by the electric force as it moves from A to B?
 J
(c)
What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.)
PEB − PEA =  J
(d)
What is the potential difference (in V) between A and B?
VB − VA =  V
A
B
+
+
d -
Transcribed Image Text:A B + + d -
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