The ethyl mercaptan concentration in a mixture was determined by shaking a 2.043-g sample with 50.00 mL of 0.01204 M 1₂ in a tightly stoppered flask: 2C₂H5SH + 12 C₂H5SSC₂H5 +21₂ + 2H+ The excess 1₂ was back-titrated with 18.23 mL of 0.01437 M Na2S2O3. Calculate the percentage of C₂H5SH (62.13 g/mol).

Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 10E: The Handbook of Chemistry and Physics (http://openstaxcollege.org/l/16Handbook) gives solubilities...
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The ethyl mercaptan concentration in a mixture was determined by shaking a 2.043-g sample
with 50.00 mL of 0.01204 M 1₂ in a tightly stoppered flask:
2C₂H5SH + 12 → C₂H5SSC₂H5 +21₂ + 2H+
The excess 1₂ was back-titrated with 18.23 mL of 0.01437 M Na₂S₂O3. Calculate the percentage of
C₂H5SH (62.13 g/mol).
Transcribed Image Text:The ethyl mercaptan concentration in a mixture was determined by shaking a 2.043-g sample with 50.00 mL of 0.01204 M 1₂ in a tightly stoppered flask: 2C₂H5SH + 12 → C₂H5SSC₂H5 +21₂ + 2H+ The excess 1₂ was back-titrated with 18.23 mL of 0.01437 M Na₂S₂O3. Calculate the percentage of C₂H5SH (62.13 g/mol).
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Chemistry by OpenStax (2015-05-04)
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ISBN:
9781938168390
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Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax