The equilibrium constant, Kp. for the following reaction is 0.110 at 298 K: NH₂HS(s) 12 NH₂(g) + H₂S(g) Calculate the equilibrium partial pressure of H₂S when 0.510 moles of NH4HS(s) is introduced into a 1.00 L vessel at 298 K. PH₂S Submit Answer atm Retry Entire Group 8 more group attempts remaining

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter12: Gaseous Chemical Equilibrium
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Problem 34QAP: At 500C, k for the for the formation of ammonia from nitrogen and hydrogen gases is 1.5105....
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The equilibrium constant, Kp. for the following reaction is 0.110 at 298 K:
NH4HS(S) 12 NH₂(g) + H₂S(g)
Calculate the equilibrium partial pressure of H₂S when 0.510 moles of NH4HS(s) is introduced into a 1.00 L vessel at 298 K.
PH₂S
Submit Answer
atm
Retry Entire Group
8 more group attempts remaining
Transcribed Image Text:The equilibrium constant, Kp. for the following reaction is 0.110 at 298 K: NH4HS(S) 12 NH₂(g) + H₂S(g) Calculate the equilibrium partial pressure of H₂S when 0.510 moles of NH4HS(s) is introduced into a 1.00 L vessel at 298 K. PH₂S Submit Answer atm Retry Entire Group 8 more group attempts remaining
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