The equilibrium constant Kc for the reaction: 12(g) == 21(g) is 3.8 x 10-5 at 727°C. Calculate Kc and Kp for the equilibrium 21(g) == 12(g) at the same temperature.

Chemistry
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Chapter17: Spontaneity, Entropy, And Free Energy
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Problem 112CWP: The equilibrium constant for a certain reaction increases by a factor of 6.67 when the temperature...
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The equilibrium constant Kc for the reaction: 1₂(g) == 21(g) is 3.8 × 10-5 at 727°C. Calculate Kc
and Kp for the equilibrium 21(g):
12(g) at the same temperature.
Transcribed Image Text:The equilibrium constant Kc for the reaction: 1₂(g) == 21(g) is 3.8 × 10-5 at 727°C. Calculate Kc and Kp for the equilibrium 21(g): 12(g) at the same temperature.
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