The equilibrium constant, K, for the following reaction is 1.20 x 10-² at 500 K. PCI 5(9) PCI3(9) + Cl₂(9) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.161 M PCI5, 0.0440 M PCI3 and 0.0440 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.0302 mol of Cl₂(g) is added to the flask? (Give your answers to three significant figures.) [PC] = 40 M [PC1₂] = 40 M ✔

Chemistry & Chemical Reactivity
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Chapter15: Principles Of Chemical Reactivity: Equilibria
Section: Chapter Questions
Problem 6PS: The equilibrium constant Kc, for the reaction 2 NOCI(g) 2 NO(g) + Cl2(g) is 3.9 103 at 300 C. A...
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The equilibrium constant, K, for the following reaction is 1.20 x 10-² at 500 K.
PCI5(9) ⇒ PC|3(g) + Cl₂(g)
An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.161 M PCI 5, 0.0440 M PCI 3 and 0.0440 M Cl₂.
What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.0302 mol of Cl₂(g) is added to the flask? (Give your answers to three significant figures.)
4.0
[PCI 5]
M
M
[PCI 3]
[Cl₂]
=
=
=
4.0
4.0
M
Transcribed Image Text:The equilibrium constant, K, for the following reaction is 1.20 x 10-² at 500 K. PCI5(9) ⇒ PC|3(g) + Cl₂(g) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.161 M PCI 5, 0.0440 M PCI 3 and 0.0440 M Cl₂. What will be the concentrations of the three gases once equilibrium has been reestablished, if 0.0302 mol of Cl₂(g) is added to the flask? (Give your answers to three significant figures.) 4.0 [PCI 5] M M [PCI 3] [Cl₂] = = = 4.0 4.0 M
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