The equation of motion of a simple harmonic oscillator is given by x(t) = 0.4 cos (nt/2 + π/4). At what time will the oscillator pass by the equilibrium position, x = 0, for the second time? O t = 1.5 sec O t = 3.5 sec O t = 0.5 sec O t = 4.5 sec Ot=2.5 sec

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter16: Oscillations
Section: Chapter Questions
Problem 9PQ: A simple harmonic oscillator has amplitude A and period T. Find the minimum time required for its...
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The equation of motion of a simple
harmonic oscillator is given by x(t) = 0.4 cos
(nt/2 + π/4). At what time will the oscillator
pass by the equilibrium position, x = 0, for
the second time?
46
O t = 1.5 sec
O t = 3.5 sec
O t = 0.5 sec
O t = 4.5 sec
t = 2.5 sec
III
Transcribed Image Text:The equation of motion of a simple harmonic oscillator is given by x(t) = 0.4 cos (nt/2 + π/4). At what time will the oscillator pass by the equilibrium position, x = 0, for the second time? 46 O t = 1.5 sec O t = 3.5 sec O t = 0.5 sec O t = 4.5 sec t = 2.5 sec III
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