The effect of an inhibitor on an enzyme was tested and the experiment gave the results below. If necessary, plot the data (Lineweaver-Burk) and determine, by inspection of the graph, what type of inhibition is involved. [S] (µM) 0.40 0.66 1.00 2.00 A. Competitive B. Non-competitive C. D. E. V (μmol/min) without Inhibitor 0.45 0.68 0.88 1.25 V (μmol/min) with 25 nM inhibitor 0.32 0.47 0.61 0.85 Uncompetitive There is no inhibitory effect at either 25 nM or 50 nM. Cannot conclude anything from the data or my graph. V (μmol/min) with 50 nM inhibitor 0.18 0.28 0.35 0.50
The effect of an inhibitor on an enzyme was tested and the experiment gave the results below. If necessary, plot the data (Lineweaver-Burk) and determine, by inspection of the graph, what type of inhibition is involved. [S] (µM) 0.40 0.66 1.00 2.00 A. Competitive B. Non-competitive C. D. E. V (μmol/min) without Inhibitor 0.45 0.68 0.88 1.25 V (μmol/min) with 25 nM inhibitor 0.32 0.47 0.61 0.85 Uncompetitive There is no inhibitory effect at either 25 nM or 50 nM. Cannot conclude anything from the data or my graph. V (μmol/min) with 50 nM inhibitor 0.18 0.28 0.35 0.50
Chapter21: Heparin Infusion Calculations
Section: Chapter Questions
Problem 1.3P
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![84. The effect of an inhibitor on an enzyme was tested and the experiment gave the results below. If necessary, plot
the data (Lineweaver-Burk) and determine, by inspection of the graph, what type of inhibition is involved.
[S]
(µM)
0.40
0.66
1.00
2.00
A. Competitive
B.
C.
V (μmol/min)
without Inhibitor
0.45
0.68
0.88
1.25
V (μmol/min)
with 25 nM inhibitor
0.32
0.47
0.61
0.85
Non-competitive
Uncompetitive
D. There is no inhibitory effect at either 25 nM or 50 nM.
Cannot conclude anything from the data or my graph.
E.
V (μmol/min)
with 50 nM inhibitor
0.18
0.28
0.35
0.50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F637a8243-98d2-45ca-8dd1-4e9d7d0f97ca%2F9976a2a7-d578-4d15-bdf5-72c76636e4b7%2Fdvnkzkf.jpeg&w=3840&q=75)
Transcribed Image Text:84. The effect of an inhibitor on an enzyme was tested and the experiment gave the results below. If necessary, plot
the data (Lineweaver-Burk) and determine, by inspection of the graph, what type of inhibition is involved.
[S]
(µM)
0.40
0.66
1.00
2.00
A. Competitive
B.
C.
V (μmol/min)
without Inhibitor
0.45
0.68
0.88
1.25
V (μmol/min)
with 25 nM inhibitor
0.32
0.47
0.61
0.85
Non-competitive
Uncompetitive
D. There is no inhibitory effect at either 25 nM or 50 nM.
Cannot conclude anything from the data or my graph.
E.
V (μmol/min)
with 50 nM inhibitor
0.18
0.28
0.35
0.50
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