The difference in electric potential between the accelerating plates in the electron gun of a TV tube is 25 kV, while the distance between them is 1.5 cm. The magnitude of the uniform electric field between the plates is 3.8 10 2 v/m. 5.6 10² v/m. O 1.7 106v/m. 11'108 v/m.
The difference in electric potential between the accelerating plates in the electron gun of a TV tube is 25 kV, while the distance between them is 1.5 cm. The magnitude of the uniform electric field between the plates is 3.8 10 2 v/m. 5.6 10² v/m. O 1.7 106v/m. 11'108 v/m.
Chapter7: Electric Potential
Section: Chapter Questions
Problem 81P: A double charged ion is accelerated to an energy of 32.0 keV by the electric field between two...
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Step 1
Given data:
Potential difference (ΔV) = 25 kV = 25000 V
Distance (d) = 1.5 cm = 0.015 m
Required:
The electric field (E)
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