The derivative of the function f is defined by f'(x) = x² - 3 sin (x - 5). What is the x-coordinate of the absolute minimum value of the function f on the closed interval [-2, 2]? You may use a calculator and round your answer to the nearest thousandth.

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.2: Derivatives Of Products And Quotients
Problem 35E
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The derivative of the function f is defined
by f'(x)=x²-3 sin (x - 5). What is
the x-coordinate of the absolute
minimum value of the function f on the
closed interval [-2, 2]? You may use a
calculator and round your answer to the
nearest thousandth.
Answer:
Transcribed Image Text:The derivative of the function f is defined by f'(x)=x²-3 sin (x - 5). What is the x-coordinate of the absolute minimum value of the function f on the closed interval [-2, 2]? You may use a calculator and round your answer to the nearest thousandth. Answer:
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