The decomposition of ammonia at 400 °C is: 2 NH3(g) = N2(g) + 3 H2(g). If the partial pressure of NH3 at equilibrium is 1.6 x 10-3 atm and the partial pressures of N2 and H2 are each 0.25 atm at equilibrium, what is the value for Kc (not Kp!) at 400°C for the forward reaction? Enter your answer in decimal format with two decimal places.
The decomposition of ammonia at 400 °C is: 2 NH3(g) = N2(g) + 3 H2(g). If the partial pressure of NH3 at equilibrium is 1.6 x 10-3 atm and the partial pressures of N2 and H2 are each 0.25 atm at equilibrium, what is the value for Kc (not Kp!) at 400°C for the forward reaction? Enter your answer in decimal format with two decimal places.
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 6RQ: Distinguish between the terms equilibrium constant and reaction quotient. When Q = K, what does this...
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![The decomposition of ammonia at 400 °C is: 2 NH3(g) = N2(g) + 3 H2(g). If the partial pressure of NH3 at equilibrium is 1.6 x 10-3 atm and the partial pressures of N2 and H2 are each
0.25 atm at equilibrium, what is the value for Kc (not Kp!) at 400°C for the forward reaction? Enter your answer in decimal format with two decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4049df69-4539-4b29-9c6c-849731832260%2Ffcd981f8-5ed1-463b-a4b5-130157bb37d3%2F4fxrvxw.jpeg&w=3840&q=75)
Transcribed Image Text:The decomposition of ammonia at 400 °C is: 2 NH3(g) = N2(g) + 3 H2(g). If the partial pressure of NH3 at equilibrium is 1.6 x 10-3 atm and the partial pressures of N2 and H2 are each
0.25 atm at equilibrium, what is the value for Kc (not Kp!) at 400°C for the forward reaction? Enter your answer in decimal format with two decimal places.
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