The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.05.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 4GP
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The P-value is  _____________________. (Round to three decimal places as needed.)

 

 

Based on the P-value, there is or is not sufficient evidence at a significance level of 0.05 to support or warrent rejection of the claim that the smokers have a mean continine level greater than the level of 2.84 ng/mL found for nonsmokers.

The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to
nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a
significance level of 0.05.
State the null and alternative hypotheses.
H₂H = 2.84
H₁: > 2.84
(Type integers or decimals. Do not round.)
The test statistic is
(Round to two decimal places as needed.)
(...)
Transcribed Image Text:The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n = 920 and the test statistic is t= 56.224. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.05. State the null and alternative hypotheses. H₂H = 2.84 H₁: > 2.84 (Type integers or decimals. Do not round.) The test statistic is (Round to two decimal places as needed.) (...)
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