The beam shown is simply supported and has lateral support only at its ends. The only service dead load is the weight of the beam. Determine whether it is satisfactory for the load shown. A992 steel (E= 345 MPa and F= 450 MPa) is used, and the 30 KN/m is a service live load. Use LRFD 30 KN/m WiL = 30 KN/m W16x 40 -Centroid W16 x 40 3m
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- A beam must be designed to the following specifications: Span length = 35 ft Beam spacing = 10 ft 2-in. deck with 3 in. of lightweight concrete fill (wc=115 pcf) for a total depth of t=5 in. Total weight of deck and slab = 51 psf Construction load = 20 psf Partition load = 20 psf Miscellaneous dead load = 10 psf Live load = 80 psf Fy=50 ksi, fc=4 ksi Assume continuous lateral support and use LRFD. a. Design a noncomposite beam. Compute the total deflection (there is no limit to be checked). b. Design a composite beam and specify the size and number of stud anchors required. Assume one stud at each beam location. Compute the maximum total deflection as follows: 1. Use the transformed section. 2. Use the lower-bound moment of inertia.The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P= 20 KN is applied. Sleel E-200 GPa A-400mm L1 m 2.0 m 0.6 m 1.5m P-20 KN Aluminum E70 GPa A-900mm L-1.5 m 1. Axial load at steel rod in kN? 2. Axial stress at steel rod in MPa? 3. Axial deformation of aluminum rod in mm? 4. Axial deformation of steel rod in mm? 5. Axial Load at aluminum rod in kN?A simply supported beam is subjected to a uniform service dead load of 15kN/m(including the weight of the beam), a uniform service live load of 30kN/m. the beam is 12 meters long and is laterally supported at the midspan, and A572 Gr.50 steel is used. Is W30x108 adequate? Assume Cb=1 by 4 d fore k h h Z S Ly 267 TH mm 19.3 757 13.8 min m 35.8 685.4 54.6 737.7 5670 x10^3 4900 x103 mm 60.8 x10 6 mm 2080 x10 3 8300 x10^9 mm www
- The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P = 20 KN is applied. Steel E200 Gra A-600mm L-I m 2.0 m 0.6m 1.5 m D. V P-20 KN Aluminum E-70 GPa A-900mm L-1.5 m What is the axial load at aluminum rod in KN?The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P 20 KN is applied. Sheel E200 GPa L-1 m 2.0 m 0.6m 1.5m P-20 KN Aluminum E-70 GPa A=900mm L-1.5 m What is the axial load at steel rod in KN?The beam shown in Figure is a two-span beam with a pin (hinge) in the center of the left span,making the beam statically determinate. There is continuous lateral support. The concentratedloads are service live loads. Determine whether a W12 × 79 of A992 steel is adequate.a. Use LRFD.b. Use ASD.
- The beam shown in Figure is a W36 x182. It is laterally supported at A and B. The 300 kip load is a service live load. Using the unfactored service loads, a. Compute Cb. Do not include the beam weight in the loading. b. Compute Cb. Include the beam weight in the loading.The beam shown in the figure has continuous lateral support of bothflanges. The uniform load is a service load consisting of 50% deadload and 50% live load. The dead load includes the weight of thebeam. If A992 steel is used, is a W16 × 31 adequate?a. Use LRFD.b. Use ASD.A simply supported beam subjected to a uniform service Dead load of 20kn/m (including the weight of the beam), a uniform service live load of 35kn/m. The beam is 12m long and is laterally supported at midspan, and A572 Gr. 50 steel is used. Assuming cb =1. Verify if w30x108 is adequate? Use fy=344 mpa
- How much service live load, in kN/m, can be supported? The member weight is the only dead load. The axial compressive load consists of a service dead load of 45 kN and a service live load of 90 kN. Do not consider moment amplification. Use NSCP 2015. a. b. LRFD. ASD. wt A kN/m mm² W460x144 1.41 18400 472 13.6 283 SECTION tw bf tf Ix Sx mm mm mm mm³ 22.2 726 3080 mm mm mm 199 6.2m W460x144 Sy Ty Zx ly mm mm³ mm 83.6 591 Zy J Cw mmº mm³ mm³ 67.4 3450 906 2440 4230 mmªDetermine whether the column shown in Figure is adequate to support 850 kN dead load 2400 kN live load. The steel material is $275. The column is HE450B. P min 4500 mm T 4500 mm Homework 4 - Compression Members - Flexural Buckling Strength QUESTION 7 According to the calculation above, we can say that the flange and web elements are slender elements nonslender elements QUESTION 8 Calculate the buckling length according to the x axis (Lcx) (unit will be mm and no need to write the unit). QUESTION 9 Calculate the buckling length according to the y axis (Lcy) (unit will be mm and no need to write the unit). ПQ2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m D