The balanced equation for the decomposition of TNT, CH5(NO₂)3, is 2 C₂H5(NO₂)3(s)→→7 C(s) +7 CO(g) + 3 N₂(g) +5 H₂O() How many moles of each product would form if 3.15 mol of C,H₂(NO₂), react? mol C mol CO mol N₂ mol H₂O

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.24PAE: 4.24 Ammonia gas can be prepared by the reaction CaO(s)+2NH4Cl(s)2NH3(g)+H2O(g)+CaCl2(s) If 112 g of...
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The balanced equation for the decomposition of TNT, C₂H5(NO₂)3, is
2 C₂H5(NO₂)3(s)→7 C(s) + 7 CO(g) + 3 N₂(g) +5 H₂O(1)
How many moles of each product would form if 3.15 mol of C₂H5(NO₂)3 react?
mol C
mol CO
mol N₂
mol H₂O
Transcribed Image Text:The balanced equation for the decomposition of TNT, C₂H5(NO₂)3, is 2 C₂H5(NO₂)3(s)→7 C(s) + 7 CO(g) + 3 N₂(g) +5 H₂O(1) How many moles of each product would form if 3.15 mol of C₂H5(NO₂)3 react? mol C mol CO mol N₂ mol H₂O
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