Homework Help is Here – Start Your Trial Now!
Science
Chemistry
The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x

The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: Fe(phen) 3 2+ +3 H 30* +3 H 20 → Fe(H 20) 62* + 3 phenH If the activation energy, E a is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1. what is the rate constant at 45°C? 9.6 x 10° min 1 1.1 x 10 min-1 9.3 x 10 min-1 1x10 min1 1.1 x

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter14: Chemical Kinetics: The Rates Of Chemical Reactions
Section: Chapter Questions
Problem 39PS: When healed lo a high temperature, cyclobutane, C4H8 decomposes to ethylene: C4H8(g) 2 C2H4(g) The...
See similar textbooks
icon
Related questions
Question
Jave niISWCI The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: 2+ Fe(phen) 3 2* +3 H 30 * + 3 H 20 → Fe(H 20) 6 + 3 phenH If the activation energy, E a, is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1, what is the rate constant at 45°C? 9.6 x 10° min-1 1.1 x 10 min 1 9.3 x 10 min 1 1.1 x 10 min 1
Transcribed Image Text:Jave niISWCI The aquation of tris(1,10-phenanthroline)iron(II) in acid solution takes place according to the following chemical equation: 2+ Fe(phen) 3 2* +3 H 30 * + 3 H 20 → Fe(H 20) 6 + 3 phenH If the activation energy, E a, is 126 kJ/mol and the rate constant at 30°C is 9.8 x 10 3 min -1, what is the rate constant at 45°C? 9.6 x 10° min-1 1.1 x 10 min 1 9.3 x 10 min 1 1.1 x 10 min 1
Expert Solution
Step 1

Given :-

Activation Energy = 126KJ/mol

Rate constant at 30℃ = 9.8×10-3 min-1

To find :-

Rate constant at 45℃ = ?

 

trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Theories of Reaction Rates
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS