The antiderivative of fix), denoted by F(x), exhibits an odd symmetry i.e., it satisfies the property R-x) = -F(x). If s(x) dr=K, 0

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter7: Integration
Section7.1: Antiderivatives
Problem 1E
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The antiderivative of fix), denoted by F(x), exhibits an odd symmetry i.e., it satisfies the property R-x) = -F(x). If
s(x) dr=K, 0<a<b, determine which of the following is true. [Assume both f(x) and F(x) are defined for all real values of x.]
“ 1+x•f(x)
dr = K+ In
x.f(x)
S"I+x7s) d¢=K(-a+b) + In-
“ 1+x•f(x)
dr= - K+ In
b
-b
-" I+x:f(x)
-dr = - K(-a+b)+In-
b.
Transcribed Image Text:The antiderivative of fix), denoted by F(x), exhibits an odd symmetry i.e., it satisfies the property R-x) = -F(x). If s(x) dr=K, 0<a<b, determine which of the following is true. [Assume both f(x) and F(x) are defined for all real values of x.] “ 1+x•f(x) dr = K+ In x.f(x) S"I+x7s) d¢=K(-a+b) + In- “ 1+x•f(x) dr= - K+ In b -b -" I+x:f(x) -dr = - K(-a+b)+In- b.
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