The amplitude of an oscillator decreases to 36.7% of its initial value in 26.5 s. Part A What is the value of the time constant? Express your answer with the appropriate units. ▸ View Available Hint(s) T= μÀ Value Units Bw. ?

The amplitude of an oscillator decreases to 36.7% of its initial value in 26.5 s. Part A What is the value of the time constant? Express your answer with the appropriate units. ▸ View Available Hint(s) T= μÀ Value Units Bw. ?

Name: The amplitude of an oscillator decreases to 36.7% of its initial valu
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: The amplitude of an oscillator decreases to 36.7% of its initial value in26.5 s.Part AWhat is the value of the time constant?Express your answer with the appropriate units.▸ View Available Hint(s)T=μÅValueSubmitUnits?

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter2: One Dimensional Motion

Section: Chapter Questions

Problem 18PQ

See similar textbooks

Similar questions

The expression x = 8.50 cos (2.40 t + /2) describes the position of an object as a function of time, with x in centimeters and t in seconds. What are the a. frequency, b. period, c. amplitude, and d. initial phase of the objects motion? e. What is the position of the particle at t = 1.45 s?
We do not need the analogy in Equation 16.30 to write expressions for the translational displacement of a pendulum bob along the circular arc s(t), translational speed v(t), and translational acceleration a(t). Show that they are given by s(t) = smax cos (smpt + ) v(t) = vmax sin (smpt + ) a(t) = amax cos(smpt + ) respectively, where smax = max with being the length of the pendulum, vmax = smax smp, and amax = smax smp2.
A simple pendulum has mass 1.20 kg and length 0.700 m. (a) What is the period of the pendulum near the surface of Earth? (b) If the same mass is attached to a spring, what spring constant would result in the period of motion found in part (a)?
A uniform annular ring of mass m and inner and outer radii a and b, respectively, is pivoted around an axis perpendicular to the plane of the ring at point P (Fig. P16.35). Determine its period of oscillation. FIGURE P16.35
For each expression, identify the angular frequency , period T, initial phase and amplitude ymax of the oscillation. All values are in SI units. a. y(t) = 0.75 cos (14.5t) b. vy (t) = 0.75 sin (14.5t + /2) c. ay (t) = 14.5 cos (0.75t + /2) 16.3
An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T. The object of mass m is removed and replaced with an object of mass 2m. When this object is set into oscillation, what is the period of the motion? (a) 2T (b) 2T (c) T (d) T/2 (e) T/2
The angular position of a pendulum is represented by the equation = 0.032 0 cos t, where is in radians and = 4.43 rad/s. Determine the period and length of the pendulum.
(a) If frequency is not constant for some oscillation, can the oscillation be simple harmonic motion? (b) Can you mink of any examples of harmonic motion where the frequency may depend on the amplitude?
An object oscillates with simple harmonic motion along the x-axis. Its displacement from the origin varies with time according to the equation =4cos(7nt+r/3)m. Where t is in seconds and the angles in the parentheses are in radians. 1. the amplitude is m. 2. the angular frequency (w) is 3. the frequency(f) = rad/s, Hz. 4 the period (T) = 5. the x-position at t=Os is m 6, the maximum speed = m/s 7. the maximum acceleration = m/s2 B. Att = 1s. the displacement x = m 9. Att =1s, the velocity is m/s 10 At t= 1s. the acceleration is m/s
ul touch ? 5:25 PM ni 59% A docs.google.com – Private 3 sec 1 sec In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, 0"max, to the maximum angular velocity, O'max, is Tt s^(-1). What is the time needed for the pendulum to complete two oscillations? 0.5 sec 1 sec 0.25 sec 4 sec 2 sec A traveling wave on a taut string with a tension force T is given by the wave
Not 81930449@students.liu.edu.lb? Switch account 15 MCQS In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, e"max, to the maximum angular velocity, O'max, is t s^(-1). What is the time needed for the pendulum to complete two oscillations? 0.5 sec 1 sec O 4 sec 2 sec 0.25 sec
A mass is on a spring undergoing oscillations a with an amplitude of A= 3.00 cm (see diagram below). It takes 0.25 s for the mass to travel from maximum extension to maximum compression. What is the angular frequency of the oscillations that the mass is undergoing? Give your answer in rad/s to 1 decimal place. Do NOT include units in your answer. www www. ww A A Your Answer: A Your Answer maximum extension a equilibrium maximum compression во W ^