The acetate ion, CH3COO–, reacts with water as a weak base: CH3COO–(aq) + H2O(l) ⇄ CH3COOH(aq) + OH–(aq), with K = 5.7 x 10-10 at 25°C. If sodium acetate were dissolved in water to make a 0.35 M solution, what would be the resulting concentration of OH–? (M) (no scientific notation)

Chemistry for Engineering Students
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ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
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Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.72PAE
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The acetate ion, CH3COO, reacts with water as a weak base:

CH3COO(aq) + H2O(l) ⇄ CH3COOH(aq) + OH(aq), with K = 5.7 x 10-10 at 25°C. If sodium acetate were dissolved in water to make a 0.35 M solution, what would be the resulting concentration of OH? (M) (no scientific notation)

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Given :-The acetate ion, CH3COO-, reach with water as a weak base:CH3COO-(aq)+ H2O(l)  CH3 COOH(aq)+ OH-(aq)with k = 5.7×10-10 at 25°c . Sodium acetate were dissolvedin water to make a 0.35 M solution.we have to find the scerultin concentration of OH-.

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