The acceleration of a particle is a constant. At t = 0 the velocity of the particle is (14.91 + 18.4j) m/s. At t = 4.6 s the velocity is 11.4j m/s. (Use the following as necessary: t. Do not include units in your answers.) (a) What is the particle's acceleration (in m/s²)? î+18.4 a = v(t) = (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin. î+ x Î+ ³) m/s² jm/s

Physics for Scientists and Engineers: Foundations and Connections
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The acceleration of a particle is a constant. At t=0 the velocity of the particle is (14.91 + 18.4ĵ) m/s. At t = 4.6 s the velocity is 11.4j m/s. (Use the following as necessary: t. Do not include units in your answers.)
(a) What is the particle's acceleration (in m/s²)?
=
î+ 18.4
v(t) =
(b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin.
r(t) =
î+
X
Î-
i) m/s
m/s
Transcribed Image Text:The acceleration of a particle is a constant. At t=0 the velocity of the particle is (14.91 + 18.4ĵ) m/s. At t = 4.6 s the velocity is 11.4j m/s. (Use the following as necessary: t. Do not include units in your answers.) (a) What is the particle's acceleration (in m/s²)? = î+ 18.4 v(t) = (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is initially at the origin. r(t) = î+ X Î- i) m/s m/s
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