The A36 tension member is connected with 6- 16 mm diameter bolt. The member is made of Plate PL 4"x8" or PL 12mmx200mm. Net reduction factor = 0.85, Fy 248MPA, Fu = 400 MPa. Calculate the following using ASD and LRFD method. 1. Tensile yield strength of the section. 2. Minimum tensile strength PL ½x 8 o o o
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- Determine the design tensile strength of plate (200x8 mm) connected to 10-mm thick gusset using 20 mm bolts as shown in the figure, if the yield and the ultimate stress of the steel used are 250 MPa and 410 MPa, respectively. Add 1mm around the bolt for the hole. Use LRFD method. Plate 8-mm thick 2 3 40+ 30 301 T 200 mm Gusset 10-mm thick 3af 30 2_3 *40 40+ 50,54 +40A plate with width of 420 mm and thickness of 13 mm is to be connected to a plate of the same width and thickness by 30 mm diameter bolts, as shown in the Figure 1. The holes are 3mm larger than the bolt diameter. The plate is A36 steel with yield strength Fy = 248MPa. Assume allowable tensile stress on net area is 0.60Fy. It is required to determine the value of b such that the net width along bolts 1-2-3-4 is equl to the net width along bolts 1-2-4. W = 420 mm t = 13 mm a = 64 mm c = 104 mm d = 195 mm Bolt Diameter = 30 mm Holes Diameter = 30 mm + 3 = 33 mm ?? = 248 MPa Allowable Tensile Stress on ?? = 0.60Fy a. Calculate the vaue of b in millimeters. b. Calculate the value of the net area for tension in plates in square millimeters. c. Calculate the value of P so that the allowable tensile stress on net area will not be exceeded.Situation 5. The angular section shown below is welded to a 12 mm gusset plate. Both materials are A36 steel with Fy = 250 MPa. The allowable tensile stress is 0.6Fy. The weld is E80 Electrode and 12 mm thickness. INNOVATIONS Properties of L 150x90x12: y = 50 shear stress of weld = 0.3Fu A = 2750 Allowable REVIEW INNOVATIE a K ➜ www A. 234 KN B. 349 KN b 13. What is the value of P without exceeding the allowable tensile the angle? C. 382 kN p. 413 kN 14. Find required length of the weld based on shear? A. 280 mm C. 300 mm D. 380 mm B. 320 mm 15. Find the required value of a? A. 108 mm B. 97.9 mm D. 185 mm NEW INNOVATIONS REVIEW INNOVATIOf REVIEW NEW INNOVATIONS
- A tension plate shown below is used to support suspended load "T". Gusset Plate Fy Fu = 400 MPa = 248 MPa 200 mm a) Determine the allowable tensile capacity of the plate if L = 240 mm. (Assume weld strength is satisfactory).1. A36 steel (Fy=36Ksi, Fu=58Ksi) is used for the tension member shown in the figure below. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the net area. PL % x14 2" 5" 2" 2. The tension member is a PL3/8 × 6 of A242 steel (Fy=50Ksi, Fu=70Ksi). It is connected to a 3/8-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in the figure below. Determine the nominal block shear strength of the tension member. inDetermine the design tensile strength of the 12 in. x 1/2 in. steel plate shown in the figure. The bolts are 3/4 in. diameter. The steel is A572 Gr. 50. Check yielding and fracture. Check Block Shear. T 3in. 73im 13in 1 3in t
- ISA 100 x 100 x 10mm (Cross sectional area = 1908mm2) serves as tensile member. This angle is welded to a gusset plate along A and B appropriately as shown. Assuming the yield strength of the steel to be 260 N/mm2 the tensile strength of the member can be taken to be approximately A ISA 100x100×10 Gusset Plate BProblem 2 A tension plate shown below is used to support suspended load "T. Gusset Plate F, = 248 MPa Fu = 400 MPa 200 mm a) Determine the allowable tensile capacity of the plate if L= 240 mm, (Assume weld strength is satisfactory).-A L 3 x 2 x ¼ is connected to a gusset plate via six bolts. The nominal diameter of the bolt is 0.25 inches, the pitch spacing is 1.75 inches, the gage spacing is 2 inches, and the thickness of the connection is (¼) inch. The yield stress is 50 Ksi and the ultimate stress is 60 Ksi. Consider section line (a-a') for the analysis. . a. What is the effective net area (Ae) of the angle section in inches2 [a-a']?(The shear lag factor is "0.80") b. What is the design tensile yielding strength in Kips for the steel member? c. What is the design tensile rupture strength in Kips for the steel member? d. What is the minimum Factor of Safety if a tensile load of 23 Kips is applied to the angle section? please make sure the answer is correct 100% I only need the final answers
- The tension member shown is an angle L150 x 90 x 10, of A36 steel, with Fy= 250 MPa and Fu= 400 MPa, and is subjected to a service DL= 150 KN and a service LL= 150 KN The bolts are 20 mm o. Use ASD. 40mm 40mn 40mm 50mm ... Compute the allowable strength based on yielding in KN.0 Compute the nominal strength based on fracture in KN.0 Check the adequacy of the section.0A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0.a) Determine the design tensile strength of the section based on yielding of the gross area.b) Determine the critical net area of the connection shown.A tension plate shown below is used to support suspended load "T". Gusset Plate- F, = 248 MPa Fu = 400 MPa %3D 200 mm a) Determine the allowable tensile capacity of the plate if L= 240 mm. (Assume weld strength is satisfactory).