The A kg collar is initially at rest on the bar at position 1 as shown in Figure Q2. The coefficient of friction between collar and the bar is given as µ = 0.1. The collar is subjected to a constant force P = 50 N horizontally. The spring has a constant k = 150 N/m and is held by cables so that it is initially compressed B cm. Suppose the spring will be compressed 100 mm further when the collar hit the spring at position 2. Here, the value of A and B depends on the 5th and 6th digit of your matric number respectively as shown in Table 1. For example, if your matric number is DD 170150 gives the value of A = 5 kg and B = 10 cm. Table 1
The A kg collar is initially at rest on the bar at position 1 as shown in Figure Q2. The coefficient of friction between collar and the bar is given as µ = 0.1. The collar is subjected to a constant force P = 50 N horizontally. The spring has a constant k = 150 N/m and is held by cables so that it is initially compressed B cm. Suppose the spring will be compressed 100 mm further when the collar hit the spring at position 2. Here, the value of A and B depends on the 5th and 6th digit of your matric number respectively as shown in Table 1. For example, if your matric number is DD 170150 gives the value of A = 5 kg and B = 10 cm. Table 1
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.81P: Calculate the horizontal force P required to push the 85-lb lawn mower at constant speed. The center...
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pls answer in hlf minutes with clear handwriting
subject (fluid mech 2)
matrix num
dd200153
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