that for every 51 incre caps with the local baseball team's logo planning to increase the p consumer survey shows 10 as per year. What should the selling price bet R(x)=price # of items Leta be the number of $1 Increases in price, 270 Let R be the revenue, y>0. R(x) = (15+x) (600-30x) price. quantity R'(x)= (600-30x)+ (-30) (15+x) - 600-30x-450-30x = 150-60× = 30(5-2x) ut Ri (x)=0 0 = 30 (5-2x) 5-2x=0 x=2.5 → # of increases FDT D(x) Interval D'(a) sol'n Tord x425 + >0 x=25 N/A =0 max x>2.5 <0 - Sub x=2.5 into 15+x = price P= 15+ x = 15+25 = 175 .: the selling price should be $17.50 +0 maximize annual revenue