T Part B How does this compare to the solubility of Mg(OH)2 in pure water? Express your answer as a ratio to two significant figures. View Available Hint(s) |2| ΑΣΦΑ -6 $1.63 107 Submit Previous Answers ?

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Chapter14: Acid- Base Equilibria
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Please use pictures as reference. Use part A information to find part B answer. Question: How does this compare to the solubility of Mg(OH)2 in pure water? Find Part B answer
Then convert the molar solubility to g per 100
Part B
How does this compare to the solubility of Mg(OH)2 in pure water?
Express your answer as a ratio to two significant figures.
View Available Hint(s)
V7 ΑΣΦ
-1.63.106
Submit
Previous Answers
$₁
X Incorrect; Try Again; 5 attempts remaining
MacBook Air
100 px
2.1x10 mol Mg(OH),
1X
1.2 x 10-8 g Mg(OH)2/100 mL
?
1X
1000 L
X
X
58.33 g Mg
1 mol Met
Transcribed Image Text:Then convert the molar solubility to g per 100 Part B How does this compare to the solubility of Mg(OH)2 in pure water? Express your answer as a ratio to two significant figures. View Available Hint(s) V7 ΑΣΦ -1.63.106 Submit Previous Answers $₁ X Incorrect; Try Again; 5 attempts remaining MacBook Air 100 px 2.1x10 mol Mg(OH), 1X 1.2 x 10-8 g Mg(OH)2/100 mL ? 1X 1000 L X X 58.33 g Mg 1 mol Met
▼
Part A
Calculate the solubility (in grams per 1.00 x 10² mL of solution) of magnesium hydroxide in a solution buffered at pH = 12.
Express your answer to two significant figures.
▸ View Available Hint(s)
S1 = 1.2x10-8 g/ (1.00 x 10² mL)
Submit
Previous Answers
✓ Correct
Begin by writing the reaction by which solid Mg(OH)2 dissolves into its constituent aqueous ions:
Mg(OH)2 (s) = Mg²+ (aq) + 2OH(aq)
Write the equilibrium expression for K
Ksp = [Mg2+][OH-]²
The solubility of Mg(OH)2 depends on the concentration of OH ions. The calculation of the OH ion concentration is summarized in the hint for this part
([OH] = 1.0 x 10-2 M). In a buffered solution, [OH-] remains constant and, therefore, the molar solubility of Mg(OH)2 equals [Mg²+]:
S₁ =
Then convert the molar solubility to g per 100 mL:
Part B
S₁ = 100 x
=
How does this compare to the solubility of Mg(OH)2 in pure water?
Express your answer as a ratio to two significant figures.
=
[Mg²+]
K
JOH
1X
1000 pa
1.2 x 10-8 g Mg(OH)2/100 mL
X
2.06x10-13
(1.0x10-2)2
2.1 x 10 9 M.
2.1x10 mol Mg(OH)
1X
X
58.33 g Mg(OH)₂
Imol Mg(OH),
Transcribed Image Text:▼ Part A Calculate the solubility (in grams per 1.00 x 10² mL of solution) of magnesium hydroxide in a solution buffered at pH = 12. Express your answer to two significant figures. ▸ View Available Hint(s) S1 = 1.2x10-8 g/ (1.00 x 10² mL) Submit Previous Answers ✓ Correct Begin by writing the reaction by which solid Mg(OH)2 dissolves into its constituent aqueous ions: Mg(OH)2 (s) = Mg²+ (aq) + 2OH(aq) Write the equilibrium expression for K Ksp = [Mg2+][OH-]² The solubility of Mg(OH)2 depends on the concentration of OH ions. The calculation of the OH ion concentration is summarized in the hint for this part ([OH] = 1.0 x 10-2 M). In a buffered solution, [OH-] remains constant and, therefore, the molar solubility of Mg(OH)2 equals [Mg²+]: S₁ = Then convert the molar solubility to g per 100 mL: Part B S₁ = 100 x = How does this compare to the solubility of Mg(OH)2 in pure water? Express your answer as a ratio to two significant figures. = [Mg²+] K JOH 1X 1000 pa 1.2 x 10-8 g Mg(OH)2/100 mL X 2.06x10-13 (1.0x10-2)2 2.1 x 10 9 M. 2.1x10 mol Mg(OH) 1X X 58.33 g Mg(OH)₂ Imol Mg(OH),
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