Suppose you are running a factory, producing some sort of widget that requires steel as a raw material. Your costs are predominantly human labor, which is $20 per hour for your workers, and the steel itself, which runs for $2,000 per ton. Suppose your revenue R is loosely modelled by the following equation: R(hs) = 100h²/3¹/3 where h represents hour of labor and s represents tons of steel. If your budget is $20,000, what is the maximum possible revenue?

College Algebra
10th Edition
ISBN:9781337282291
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 5ECP
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Suppose you are running a factory, producing some sort of widget that requires steel as a raw material. Your
costs are predominantly human labor, which is $20 per hour for your workers, and the steel itself, which runs
for $2,000 per ton. Suppose your revenue R is loosely modelled by the following equation:
R(hs) = 100h²/31/3
where h represents hour of labor and s represents tons of steel. If your budget is $20,000, what is the
maximum possible revenue?
Transcribed Image Text:Suppose you are running a factory, producing some sort of widget that requires steel as a raw material. Your costs are predominantly human labor, which is $20 per hour for your workers, and the steel itself, which runs for $2,000 per ton. Suppose your revenue R is loosely modelled by the following equation: R(hs) = 100h²/31/3 where h represents hour of labor and s represents tons of steel. If your budget is $20,000, what is the maximum possible revenue?
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